Q7
In the following figure, the area of the isosceles right triangle ABE is 7 sq.cm. If EC = 3BE, then the area of rectangle ABCD (in sq. cm.) is
Answer: D
∵ The area of the ∆ABE = AB × BE = 7 cm2
∴ BE × AB = 14
The area of the rectangle ABCD = AB × BC = AB × (BE + EC) = 4 × (BE × AB) = 56 cm2
Hence, option (d).