Which of the following parties received maximum number of “neutral tweets” in the year 2010?
Answer: A
Number of “natural tweets” for B, C, D and E are:
Party B: (100 – 30.4 – 29.7)% of 108128 = 0.399 × 108128
Party C: (100 – 32.5 – 26.6)% of 96620 = 0.409 × 96620 = (0.399 + 0.01) × 96620
Party D: (100 – 30.6 – 36.1)% of 41524 = 0.333 × 41524
Party E: (100 – 21.6 – 41.0)% of 32724 = 0.374 × 32724
Both the total number of tweets and the percentage of neutral tweets of B and C are greater than those of D and E. Hence, options 3 and 4 are eliminated.
Among B and C, number for party B is more than C.
Number of neutral tweets of B ≈ 0.4 × 108128 = 43251.2
Parties classified under ‘Other Parties’ have a total of 15000 tweets, which is significantly lower than the total number of tweets of the rest of the parties. Thus, ‘Other Parties’ cannot have the maximum number of neutral tweets even if all 15000 tweets are neutral. Hence, option (e) is eliminated.
Hence, option (a).