CAT 1997 QA Question 30 · Algebra - Functions & Graphs

le (15,min (10, 6),le (9,8,ma (15,10,9)))
Now ma(15,10, 9) = $\frac{1}{2}$ [le(15, 10, 9) + la(15, 10, 9)]

= $\frac{1}{2}$ [max(5, 1) + min(25,19)]

= $\frac{1}{2}$ (5 + 19) = 12

Hence, our original expression would now be
le(15,min(10,6),le(9,8,12))
= le(15, 6,max(1, − 4))
= le(15, 6,1) = max(9, 5) = 9