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Explanation:

Let the radius of the circle be 'r'.

∴ AB = CD = 2r

Let O be the center of the circle

AOC is a right triangle, where AO = OC = r

⇒ AC2 = AO2 + OC2 

⇒ AC2 = r2 + r2 = 2r2 

⇒ AC = √2 × r = √2 × AB/2

⇒ AC = AB/√2

Hence, option (b).

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