In the following figure, ∆ABC is an inscribed triangle as shown and DE is an tangent to the circle at C. If m∠ACD = 65° and m∠ACB = 35°, find the measure of m∠BAC
Explanation:
In the given circle, m∠ACD = m∠ABC = 65° [Anglel made by tangent and a chord is same as angle subtended by same chord in opposite segment of the circle.]
In ∆ABC, ∠ABC + ∠BCA + ∠CAB = 180° ∴ 65° + 35° + ∠CAB = 180° ⇒ ∠CAB = 80°
Hence, option (a).
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