Discussion

Explanation:

Given, 2z = x + y
⇒ z - x = y - z

Now xx-z + yy-z = xx-z + yz-x

xx-z + yy-z = xx-z - yx-z

xx-z + yy-z = x-yx-z

xx-z + yy-z = x-yx-(x+y)2 = 2

∴ xx-z + yy-z = 2

Alternately,
Assume x = 2 and y = 4, hence z = 3

Now, xx-z + yy-z  = 22-3 + 44-3 = -2 + 4 = 2 

Hence, option (c).

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