SSC CHSL 9th June Shift 2 Previous Year Paper Quantitative Aptitude questions | CHSL Past Year Papers

1. SSC CHSL 9th June Shift 2 - QA | Percentage, Profit & Loss - SSC

The difference between a discount of 35% and two successive discounts of 20% and 20% on a certain bill, was ₹22. Find the amount of the bill.

A.
₹2,800
B.
₹2,200
C.
₹3,200
D.
₹2,000

2. SSC CHSL 9th June Shift 2 - QA | Time, Speed & Distance - SSC

Riya runs 3/2 times as fast as Prerna. In a race, if Riya gives a lead of 100 m to Prerna, find the distance Riya has to run before both of them meet.

A.
315 m
B.
300 m
C.
265 m
D.
240 m

Answer: Option B

Explanation :

Ratio of speeds of Riya and Prerna = 3 : 2

Let Prerna run P meters before Riya catches up with her.
⇒ Distance travelled by Riya = P + 100

∴ $\frac{Distance covered by Riya}{Distance covered by Prerna}$ = $\frac{P + 100}{P}$ = $\frac{3}{2}$

⇒ 2P + 200 = 3P

⇒ P = 200

∴ Distance travelled by Riya = P + 100 = 300 meters.

Hence, option (b).

3. SSC CHSL 9th June Shift 2 - QA | Simplification - SSC

Simplify the following: 50% of [6 - {15 - [6 + 8 ÷ (5 - 3)] + 2}].

A.
12.5
B.
1.5
C.
4
D.
200

4. SSC CHSL 9th June Shift 2 - QA | Tables & Graphs - SSC

The given pie chart presents the monthly expenses on various heads and the savings of Mr.X's family. Study the pie chart and answer the question that follows.

In the total income of Mr.X is ₹1,20,000, then how much does he pay for transport.

A.
₹15,000
B.
₹12,000
C.
₹20,000
D.
₹10,000

Answer: Option D

Explanation :

Amount paid for transport = $\frac{30 °}{360 °}$ × 1,20,000 = 10,000

Hence, option (d).

5. SSC CHSL 9th June Shift 2 - QA | Percentage, Profit & Loss - SSC

While selling to the retailer, a company allows 30% discount on the marked price of its products. If the retailer sells those products at marked price, his profit per cent will be ________.

A.
$42 \frac{8}{7}$
B.
$42 \frac{6}{7}$
C.
$42 \frac{4}{7}$
D.
$42 \frac{2}{7}$

6. SSC CHSL 9th June Shift 2 - QA | Percentage, Profit & Loss - SSC

A shopkeeper sold an article for ₹1,326 after allowing a discount of 15% on its marked price. Find the marked price of the article.

A.
₹1,153
B.
₹ 1,560
C.
₹1,525
D.
₹1,650

7. SSC CHSL 9th June Shift 2 - QA | Number Theory - SSC

If (x + 2) and (x - 3) are the factors of x² + k₁x + k₂, then:

A.
k₁ = 1 and k₂ = -6
B.
k₁ = -1 and k₂ = -6
C.
k₁ = -1 and k₂ = 6
D.
k₁ = 1 and k₂ = 6

8. SSC CHSL 9th June Shift 2 - QA | Mensuration - SSC

In a right circular cone, the radius of the base is 14 cm and the height is 48 cm. A cross-section is made through the midpoint of the height parallel to the base. The volume of the upper portion is:

(Take π = 22/7).

A.
1102 cm²
B.
1232 cm²
C.
1120 cm²
D.
1442 cm²

Answer: Option B

Explanation :

We know, for frustum of a cone ratio of volume of smaller cone to bigger cone is cube of the ratio of heights.

∴ $\frac{Volume of smaller cone}{Volume of larger cone}$ = ${(\frac{h / 2}{h})}^{3}$ = $\frac{1}{8}$

⇒ Volume of smaller cone = $\frac{1}{8}$ × $\frac{1}{3}$ πr2h

⇒ Volume of smaller cone = $\frac{1}{8}$ × $\frac{1}{3}$ × $\frac{22}{7}$ × 142 × 48 = 1232

Hence, option (b).

9. SSC CHSL 9th June Shift 2 - QA | Simple & Compound Interest - SSC

On a sum of money, when invested for 2 years, compound interest and simple interest are ₹300 and ₹250, respectively. For both simple and compound interests the rate of interest per annum is the same, and for compound interest, interest is compounded annually. Find the rate of interest per annum.

A.
10%
B.
20%
C.
40%
D.
30%

10. SSC CHSL 9th June Shift 2 - QA | Number Theory - SSC

Find the greatest possible value of (a + b) for which the 8-digit number 143b203a is divisible by 15.

A.
15
B.
17
C.
16
D.
14

11. SSC CHSL 9th June Shift 2 - QA | Time, Speed & Distance - SSC

Gopal travels from A to B at the speed of 5km/h, from B to C at 10 km/h, and from C to D at 15 km/h. If AB = BC = CD, then find Gopal’s average speed.

A.
$8 \frac{2}{11}$
B.
$70 \frac{2}{11}$
C.
$60 \frac{2}{11}$
D.
$9 \frac{2}{11}$

12. SSC CHSL 9th June Shift 2 - QA | Ratio, Proportion & Variation - SSC

P, Q and R are batsmen. The ratio of the runs scored by them in a certain match was P ∶ Q = 16 : 17 and Q : R = 15 ∶ 16. At the end of the match, they scored a total of 956 runs. The number of runs scored by R is (nearest to an integer):

A.
440
B.
335
C.
339
D.
430

13. SSC CHSL 9th June Shift 2 - QA | Tables & Graphs - SSC

Study the following table and answer the question that follows:

The following table gives the month-wise number of different types of scooters produced by a company during the first six months of 1992.

In which month, did the company produce an equal number of scooters of each type?

A.
May
B.
January
C.
March
D.
June

14. SSC CHSL 9th June Shift 2 - QA | Average, Mixture & Alligation - SSC

The average weight of 8 men is increased by 1.5 kg when one of the men who weighs 65 kg is replaced by a new man. The weight of the new man is:

A.
71 kg
B.
87 kg
C.
81 kg
D.
77 kg

15. SSC CHSL 9th June Shift 2 - QA | Number Theory - SSC

If k + $(\frac{1}{k})$ = 2, find the value of 8k × k × k.

A.
8
B.
1
C.
4
D.
2

Answer: Option A

Explanation :

For any positive number k, k + $(\frac{1}{k})$ = 2 only when k = 1/k = 1

∴ 8k × k × k = 8 × 1 × 1 × 1 = 8

Hence, option (a).

16. SSC CHSL 9th June Shift 2 - QA | Percentage, Profit & Loss - SSC

There is a continuous growth in the population of a village at the rate of 5% per annum. If its present population is 18522, what was the population of the village 3 years ago?

A.
17500
B.
16400
C.
16000
D.
17200

Answer: Option C

Explanation :

Initial Population = $\frac{18522}{1.05 \times 1.05 \times 1.05}$ = 16000

Hence, option (c).

17. SSC CHSL 9th June Shift 2 - QA | Time & Work - SSC

If 15 boys earn ₹900 in 5 days, then how much will 20 boys earn in 7 days?

A.
₹1,580
B.
₹1,680
C.
₹1,540
D.
₹1,650

18. SSC CHSL 9th June Shift 2 - QA | Circles - SSC

In a circle, AB and CD are two diameters which are perpendicular to each other. Find the length of chord AC.

A.
$\sqrt{2}$ CD
B.
$\frac{A B}{\sqrt{2}}$
C.
$\frac{C D}{2}$
D.
2 AB

19. SSC CHSL 9th June Shift 2 - QA | Percentage, Profit & Loss - SSC

The expenditure of a company increases by 25%, then increases by 30%, then further decreases by 20%.The overall percentage change in expenditure is:

A.
10
B.
30
C.
34
D.
22

20. SSC CHSL 9th June Shift 2 - QA | Tables & Graphs - SSC

The following table shows the marks (in percentages) obtained by six students in four different subjects in an examination.

The maximum marks in each subject is 100.

Answer the following questions based on the table:

In which of the following subjects is the average of the percentage marks obtained by the six students the highest?

A.
Maths
B.
Geography
C.
Chemistry
D.
Physics

21. SSC CHSL 9th June Shift 2 - QA | Simplification - SSC

Simplify:

$\frac{{(r - s)}^{3} + {(s - t)}^{3} + {(t - r)}^{3}}{6 (r - s) (s - t) (t - r)}$

A.
$\frac{1}{6}$
B.
$\frac{1}{2}$
C.
$\frac{1}{3}$
D.
$\frac{1}{4}$

Answer: Option B

Explanation :

Given, $\frac{{(r - s)}^{3} + {(s - t)}^{3} + {(t - r)}^{3}}{6 (r - s) (s - t) (t - r)}$

We know, if a + b + c = 0, then a³ + b³+ c³ = 3abc

Here, (r - s) + (s - t) + (t - r) = 0

∴ (r - s)³ + (s - t)³ + (t - r)³ = 3(r - s)(s - t)(t - r)

∴ $\frac{{(r - s)}^{3} + {(s - t)}^{3} + {(t - r)}^{3}}{6 (r - s) (s - t) (t - r)}$ = $\frac{3 (r - s) (s - t) (t - r)}{6 (r - s) (s - t) (t - r)}$ = $\frac{1}{2}$

Hence, option (b).

22. SSC CHSL 9th June Shift 2 - QA | Percentage, Profit & Loss - SSC

By using faulty weight, a shopkeeper cheats to the extent of 6% while buying and selling rice. Find his gain percentage (rounded to two decimal places).

A.
14.66%
B.
13.65%
C.
12.77%
D.
11.25%

23. SSC CHSL 9th June Shift 2 - QA | Mensuration - SSC

The radius of a roller is 14 cm and its length 20 cm. It takes 235 complete revolutions to move once over to level a playground. Find the area of the playground.

(Use π = 22/7)

A.
4136 cm²
B.
4136 × 10³ cm²
C.
41360 cm²
D.
4136 × 10² cm²

24. SSC CHSL 9th June Shift 2 - QA | Trigonometry - SSC

If α is an acute angle, which of the following options will NOT necessarily be equal to the value of cosec α?

A.
$\frac{1}{\cos α}$
B.
$\sqrt{1 + c o t^{2} α}$
C.
$\frac{1}{\sin α}$
D.
$\frac{c o t α}{\cos α}$

Answer: Option A

Explanation :

We know, $\frac{1}{\cos α}$ = sec α

Hence, option (a).

25. SSC CHSL 9th June Shift 2 - QA | Mensuration - SSC

Find the total surface area of a cylinder with diameter of base 28 cm and height 70 cm.

A.
7300 cm²
B.
7932 cm²
C.
8000 cm²
D.
7392 cm²

SSC CHSL 9th June Shift 2 - QA

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