# SSC CHSL 8th June Shift 2 - QA

**1. SSC CHSL 8th June Shift 2 - QA | Trigonometry - SSC**

If sin θ = $\frac{12}{13}$, 0 < θ < 90°, then $\frac{{\mathrm{sin}}^{2}\theta -{\mathrm{cos}}^{2}\theta}{2\mathrm{sin}\theta .\mathrm{cos}\theta}$ × $\frac{1}{{\mathrm{tan}}^{2}\theta}$ = __________.

- A.
$\frac{295}{3456}$

- B.
$\frac{590}{3542}$

- C.
$\frac{695}{3542}$

- D.
$\frac{595}{3456}$

Answer: Option D

**Explanation** :

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**2. SSC CHSL 8th June Shift 2 - QA | Simplification - SSC**

What is the value of the following expression?

${2}^{2}$${\left(\frac{{x}^{a}}{{x}^{b}}\right)}^{(a+b)}$ × ${3}^{2}$ ${\left(\frac{{x}^{b}}{{x}^{c}}\right)}^{(b+c)}$ × ${6}^{-2}$ ${\left(\frac{{x}^{2}}{{x}^{a}}\right)}^{(a+c)}$

- A.
1

- B.
0

- C.
4

- D.
9

Answer: Option A

**Explanation** :

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**3. SSC CHSL 8th June Shift 2 - QA | Operator Based Questions - SSC**

What value must be given to ‘*’ to make 6347*25 exactly divisible by 11?

- A.
1

- B.
2

- C.
8

- D.
0

Answer: Option C

**Explanation** :

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**4. SSC CHSL 8th June Shift 2 - QA | Average, Mixture & Alligation - SSC**

The average weight of each box in a consignment of 20 boxes of mangoes and 15 boxes of apples is 30 kg. If the average weight of a box of mangoes is 35 kg, then what is the average weight of a box of apples?

- A.
$\frac{70}{3}$ kg

- B.
$\frac{75}{2}$ kg

- C.
$\frac{70}{5}$ kg

- D.
$\frac{26}{5}$ kg

Answer: Option A

**Explanation** :

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**5. SSC CHSL 8th June Shift 2 - QA | Average, Mixture & Alligation - SSC**

The average runs of a cricket player in 20 matches is 30. If the average of the first 12 matches is 40, find the average of the last 8 matches.

- A.
14

- B.
15

- C.
16

- D.
8

Answer: Option B

**Explanation** :

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**6. SSC CHSL 8th June Shift 2 - QA | Tables & Graphs - SSC**

The following table shows the number of students of seven colleges participating in extra-curricular activities. Study the table and answer the question that follows.

The colleges in which the minimum number of students participate in extra-curricular activities are:

- A.
E and G

- B.
A and E

- C.
D and G

- D.
B and D

Answer: Option C

**Explanation** :

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**7. SSC CHSL 8th June Shift 2 - QA | Simplification - SSC**

If x - $\frac{1}{x}$ = 11 and x > 0, What is the value of (x² - $\frac{1}{{x}^{2}}$)?

- A.
-11$\sqrt{123}$

- B.
55$\sqrt{5}$

- C.
11$\sqrt{123}$

- D.
-55$\sqrt{5}$

Answer: Option B

**Explanation** :

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**8. SSC CHSL 8th June Shift 2 - QA | Percentage, Profit & Loss - SSC**

The ratio of the cost price to the marked price of an article is 4 ∶ 7. A discount of 25% is given on the marked price and the shopkeeper made a profit of ₹50. Find the cost price of the article.

- A.
₹160

- B.
₹165

- C.
₹150

- D.
₹155

Answer: Option A

**Explanation** :

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**9. SSC CHSL 8th June Shift 2 - QA | Percentage, Profit & Loss - SSC**

A shopkeeper claims that he is selling sugar at Rs.27/kg which cost him Rs.30/kg, but he gives 750 grams instead of 1000 grams. What is his profit or loss percentage?

- A.
10% loss

- B.
7.5% profit

- C.
b:5 %loss

- D.
20% profit

Answer: Option D

**Explanation** :

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**10. SSC CHSL 8th June Shift 2 - QA | Time, Speed & Distance - SSC**

Two trains having lengths of 230 m and 240 m are 130 m apart. They start moving towards each other on parallel tracks, at speeds of 160 km/h and 200 km/h, respectively. In how much time will the trains cross each other?

- A.
5 sec

- B.
6 sec

- C.
8 sec

- D.
7 sec

Answer: Option B

**Explanation** :

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**11. SSC CHSL 8th June Shift 2 - QA | Percentage, Profit & Loss - SSC**

40% of the cost price of an article is equal to 30% of its selling price. The approximate percentage of profit or loss on the cost price is:

- A.
44.44% profit

- B.
4b:22% loss

- C.
35.55% loss

- D.
3c:33% profit

Answer: Option D

**Explanation** :

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**12. SSC CHSL 8th June Shift 2 - QA | Simplification - SSC**

Find the radius of the circle x^{2} + y^{2} - 4x + 6y = 12.

- A.
4

- B.
3

- C.
5

- D.
2

Answer: Option C

**Explanation** :

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**13. SSC CHSL 8th June Shift 2 - QA | Tables & Graphs - SSC**

The pie chart shows the percentage-wise break up of students in terms of specialisation in Engineering.

Total number of students = 8000

What is the total number of students having specialisation in Operating system, java and DBMS?

- A.
4640

- B.
5260

- C.
4008

- D.
4160

Answer: Option D

**Explanation** :

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**14. SSC CHSL 8th June Shift 2 - QA | Simple & Compound Interest - SSC**

In what time will ₹3,90,625 amount to ₹4,56,976 at 8 % per annum, interest being compounded half-yearly?

- A.
2 years

- B.
1$\frac{1}{2}$ years

- C.
2$\frac{1}{2}$ years

- D.
1 year

Answer: Option A

**Explanation** :

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**15. SSC CHSL 8th June Shift 2 - QA | Simple & Compound Interest - SSC**

Find the compound interest on ₹1,60,000 at 10% per annum for 2 years if the interest is compounded half-yearly.

- A.
₹32,282

- B.
₹34,481

- C.
₹33,458

- D.
₹35,550

Answer: Option B

**Explanation** :

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**16. SSC CHSL 8th June Shift 2 - QA | Time & Work - SSC**

A, B and C can do a work in 5 days,6 days and 10 days, respectively. Working together, in how many days will they finish the same work?

- A.
2$\frac{1}{7}$

- B.
4$\frac{1}{7}$

- C.
3$\frac{1}{7}$

- D.
1$\frac{1}{7}$

Answer: Option A

**Explanation** :

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**17. SSC CHSL 8th June Shift 2 - QA | Circles - SSC**

Each edge of the following square is 20 cm long, and a circle is inscribed in the square as shown. What is the area of the shaded region?

[Use π = 3.14]

- A.
88 cm

^{2} - B.
85 cm

^{2} - C.
86 cm

^{2} - D.
84 cm

^{2}

Answer: Option C

**Explanation** :

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**18. SSC CHSL 8th June Shift 2 - QA | Circles - SSC**

The diameter of the base of a right-circular cylinder is 12 cm and the height of the cylinder is 2.45 times the radius of its base.

Find the volume of the cylinder [Use π = 3.14]

- A.
1636.2 cm

^{3} - B.
1666.2 cm

^{3} - C.
1663:2 cm

^{3} - D.
1665.2 cm

^{3}

Answer: Option C

**Explanation** :

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**19. SSC CHSL 8th June Shift 2 - QA | Simplification - SSC**

If y varies directly with x, and y = 61 when x = 42, find y when x = 54 (consider integral value).

- A.
86

- B.
78

- C.
82

- D.
72

Answer: Option B

**Explanation** :

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**20. SSC CHSL 8th June Shift 2 - QA | Triangles - SSC**

What is the area of an equilateral triangle whose each sides is 12 cm?

- A.
36$\sqrt{3}$ cm²

- B.
38$\sqrt{3}$ cm²

- C.
34$\sqrt{3}$ cm²

- D.
40$\sqrt{3}$ cm²

Answer: Option A

**Explanation** :

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**21. SSC CHSL 8th June Shift 2 - QA | Simplification - SSC**

Simplify the following expression.

$\frac{17.{46}^{2}-4.{46}^{2}}{17.46+4.46}$

- A.
13

- B.
17

- C.
21.92

- D.
4

Answer: Option A

**Explanation** :

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**22. SSC CHSL 8th June Shift 2 - QA | Ratio, Proportion & Variation - SSC**

The salaries of X, Y and Z are in the ratio 2 : 3 : 5. By what percentage is the salary of Z more than that of X?

- A.
100

- B.
200

- C.
120

- D.
150

Answer: Option D

**Explanation** :

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**23. SSC CHSL 8th June Shift 2 - QA | Average, Mixture & Alligation - SSC**

The average of two numbers is 96. If 2 is added to the smaller number, the ratio between the numbers becomes 2 : c: The smaller number is _________.

- A.
116.4

- B.
133:4

- C.
75.6

- D.
59.6

Answer: Option C

**Explanation** :

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**24. SSC CHSL 8th June Shift 2 - QA | Simplification - SSC**

What is the value of [$\frac{1}{5}$ + {$\frac{1}{7}$ of ($\frac{25}{42}$ ÷ $\frac{35}{6}$) - ($\frac{4}{7}$ × $\frac{6}{5}$ ÷ $\frac{54}{63}$} + $\frac{28}{40}$]

- A.
$\frac{403}{3430}$

- B.
$\frac{99}{490}$

- C.
$\frac{383}{3430}$

- D.
$\frac{393}{3430}$

Answer: Option D

**Explanation** :

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**25. SSC CHSL 8th June Shift 2 - QA | Tables & Graphs - SSC**

**Study the given table carefully to answer the question that follows.**

The following table gives the information about the populations of five different cities in the year 2020.

The number of children in city S is:

- A.
6130

- B.
6820

- C.
6310

- D.
6280

Answer: Option D

**Explanation** :

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