# SSC CHSL 31st May Shift 2 - QA

**1. SSC CHSL 31st May Shift 2 - QA | Percentage, Profit & Loss - SSC**

By selling a fridge for ₹18,200, Anu loses 15%. Find the cost price of the fridge.

(Consider integral part only)

- A.
₹21,820

- B.
₹21,411

- C.
₹19,680

- D.
₹19,411

Answer: Option B

**Explanation** :

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**2. SSC CHSL 31st May Shift 2 - QA | Percentage, Profit & Loss - SSC**

The marked price of a mobile phone is ₹18,000. It is sold with two successive discounts of 25% and 4%. An additional discount of 5% is offered for cash payment. The selling price of the mobile on cash payment is:

- A.
₹12,312

- B.
₹12,123

- C.
₹12,132

- D.
₹12,231

Answer: Option A

**Explanation** :

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**3. SSC CHSL 31st May Shift 2 - QA | Time, Speed & Distance - SSC**

In still water, the speed of a motorboat is 15 km/h. The boat travels 30 km downstream and returns in 4 hours and 30 minutes. The stream's speed (in km/h) is:

- A.
4

- B.
7

- C.
5

- D.
3

Answer: Option C

**Explanation** :

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**4. SSC CHSL 31st May Shift 2 - QA | Tables & Graphs - SSC**

The table below gives the numbers of students from five different colleges who participated in the Olympiads of five different subjects during a given year.

Find the average number of students per college who participated in the English Olympiad

- A.
105

- B.
106

- C.
104

- D.
100

Answer: Option A

**Explanation** :

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**5. SSC CHSL 31st May Shift 2 - QA | Percentage, Profit & Loss - SSC**

A cot was marked for ₹15,000 but sold for ₹13,500. What was the discount percentage offered on it?

- A.
20%

- B.
15%

- C.
10%

- D.
12%

Answer: Option C

**Explanation** :

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**6. SSC CHSL 31st May Shift 2 - QA | Percentage, Profit & Loss - SSC**

Two years ago,the population of a village was 1,000. The population increased by 10% is the first year and decreased by 10% in the second year. Find the present population.

- A.
985

- B.
980

- C.
990

- D.
995

Answer: Option C

**Explanation** :

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**7. SSC CHSL 31st May Shift 2 - QA | Simplification - SSC**

If x = 5t and y = $\frac{1}{3}$ (t + 1), then the value of x = 3y is:

- A.
$\frac{1}{3}$

- B.
$\frac{1}{2}$

- C.
$\frac{1}{4}$

- D.
$\frac{1}{5}$

Answer: Option C

**Explanation** :

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**8. SSC CHSL 31st May Shift 2 - QA | Number Theory - SSC**

If the number 732XY is divisible by 70, then find the minimum value of $\frac{X+Y}{2}$.

- A.
2

- B.
1

- C.
0

- D.
3

Answer: Option B

**Explanation** :

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**9. SSC CHSL 31st May Shift 2 - QA | Simplification - SSC**

If X > 0 and ${X}^{4}$ + $\frac{1}{{X}^{4}}$ = 2207, what is the value of $\left({X}^{5}+\frac{1}{{X}^{5}}\right)$

- A.
15127

- B.
15134

- C.
15141

- D.
15130

Answer: Option A

**Explanation** :

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**10. SSC CHSL 31st May Shift 2 - QA | Percentage, Profit & Loss - SSC**

As part of Diwali offer, a jeweller allows a discount of 15%. Even after giving the discount, he makes a profit of 6.25%. Rani bought a gold chain which was marked at ₹5,000 from this jeweller. Find the cost price of the chain for the jeweller.

- A.
₹5,000

- B.
₹4,400

- C.
₹3,400

- D.
₹4,000

Answer: Option D

**Explanation** :

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**11. SSC CHSL 31st May Shift 2 - QA | Average, Mixture & Alligation - SSC**

The average weight of 18 boys in a class is 45 kg and that of the remaining 8 boys is 48.75 kg. Find the average weight (in kg) of all the boys in the class.(Correct to two decimal places)

- A.
47.5

- B.
44.98

- C.
46.15

- D.
42

Answer: Option C

**Explanation** :

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**12. SSC CHSL 31st May Shift 2 - QA | Average, Mixture & Alligation - SSC**

If m is a natural number, then the average of five consecutive natural numbers, starting with m, is:

- A.
2m

- B.
m + 2

- C.
$\frac{(4m+6)}{5}$

- D.
5m + 10

Answer: Option B

**Explanation** :

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**13. SSC CHSL 31st May Shift 2 - QA | Time & Work - SSC**

If 5 persons can prepare 5 tables in 5 days, then how long will it take 25 persons to prepare 25 tables?

- A.
25 days

- B.
15 days

- C.
20 days

- D.
5 days

Answer: Option D

**Explanation** :

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**14. SSC CHSL 31st May Shift 2 - QA | Trigonometry - SSC**

What is the value of (4 sin^{3} x - 3 sin x + sin 3x)?

- A.
1

- B.
0

- C.
4

- D.
3

Answer: Option B

**Explanation** :

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**15. SSC CHSL 31st May Shift 2 - QA | Average, Mixture & Alligation - SSC**

The average weight of a family of 4 members is 45 kg. The grandfather and the grandmother come to visit the family. Now the average weight of the 6 members of the family is 48 kg. Find the average weight of the grandparents (in kg).

- A.
53

- B.
52

- C.
51

- D.
54

Answer: Option D

**Explanation** :

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**16. SSC CHSL 31st May Shift 2 - QA | Circles - SSC**

A chord of 10 cm passes through the centre of a circle. What is the diameter of the circle?

- A.
5 cm

- B.
15 cm

- C.
20 cm

- D.
10 cm

Answer: Option D

**Explanation** :

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**17. SSC CHSL 31st May Shift 2 - QA | Simplification - SSC**

(2x + 3y + 4z) (4x^{2} + 9y^{2} + 16z^{2 }− 6xy − 12yz − 8xz) =?

- A.
8x

^{3}+ 27y^{3}+ 64z^{3}+ 72xyz - B.
8x

^{3}+ 27y^{3}+ 64z^{3}− 72xyz - C.
8x

^{3}+ 27y3 − 64z^{3}+ 72xyz - D.
8x

^{3}− 27y^{3}− 64z^{3}− 72xyz

Answer: Option B

**Explanation** :

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**18. SSC CHSL 31st May Shift 2 - QA | Tables & Graphs - SSC**

Study the given table and answer the question that follows.

If the company had initally issued 10000 shares between its four partners, and if Tanmay then sold 1000 of his shares to Dhanya, then how many shares did Dhanya finally have?

- A.
3000

- B.
4000

- C.
3500

- D.
4500

Answer: Option D

**Explanation** :

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**19. SSC CHSL 31st May Shift 2 - QA | Tables & Graphs - SSC**

The following bar graph shows the data of the number of students of different classes who like to eat different types of fruits.

What percentage of the students of class 8 mentaioned here like guavas?

- A.
36%

- B.
50%

- C.
16$\frac{2}{3}$%

- D.
60%

Answer: Option C

**Explanation** :

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**20. SSC CHSL 31st May Shift 2 - QA | Coordinate Geometry - SSC**

Find the area of the given quadrilateral ABCD.

- A.
50 cm

^{2} - B.
35 cm

^{2} - C.
45 cm

^{2} - D.
40 cm

^{2}

Answer: Option D

**Explanation** :

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**21. SSC CHSL 31st May Shift 2 - QA | Circles - SSC**

The diameter of a solid hemisphere is 10 cm. Find its total surface area

(use π = 3.14).

- A.
288 cm

^{2} - B.
265.8 cm

^{2} - C.
235.5 cm

^{2} - D.
245 cm

^{2}

Answer: Option C

**Explanation** :

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**22. SSC CHSL 31st May Shift 2 - QA | Circles - SSC**

A cone-shaped temple top has slant height of 10 m and radius of base is 11 m. Find the total cost for painting its curved surface area at the rate of ₹7/m^{2}

^{[Use π = 22/7]}

- A.
₹2,440

- B.
₹2,040

- C.
₹2,420

- D.
₹2,240

Answer: Option C

**Explanation** :

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**23. SSC CHSL 31st May Shift 2 - QA | Ratio, Proportion & Variation - SSC**

Two numbers, A and B, are such that the sum of 10% of A and 8% of B is th of the sum of 12% of A and 16% of B. The ratio A : 8 is:

- A.
2 : 3

- B.
4 : 7

- C.
2 : 7

- D.
4 : 3

Answer: Option B

**Explanation** :

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**24. SSC CHSL 31st May Shift 2 - QA | Ratio, Proportion & Variation - SSC**

Find the mean proportional between 144 and 225.

- A.
$\frac{4}{5}$

- B.
$\frac{27}{2}$

- C.
180

- D.
$\frac{5}{4}$

Answer: Option C

**Explanation** :

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**25. SSC CHSL 31st May Shift 2 - QA | Simplification - SSC**

$\left[2\frac{1}{4}\xf7\frac{3}{4}\right]$ + $\left[5\frac{2}{3}\xf7\frac{17}{13}\right]$ - $\left[3\frac{1}{3}\times \frac{6}{5}\right]$ + [17.98 ÷ 6.2] + [1.25 ÷ 0.5] = ?

- A.
3.9

- B.
69.2

- C.
8.7

- D.
4.5

Answer: Option C

**Explanation** :

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