Actual IPMAT - Indore questions on this topic from past papers, newest first. Each links back to its paper.
A polynomial p(x) leaves a remainder 2 when divided by (x – 1) and a remainder 1 when divided by (x – 2). The remainder when P(x) is divided by (x -1)(x – 2) is
Answer: B
A written solution for this question isn't available yet.
The number of four-digit integers which are greater than 1000 and divisible by both 2 and 3, but not by 5, is
Answer: C
Required numbers
= Numbers which are divisible by both 2 and 3 - Numbers which are divisible by both 2, 3 and 5
= Numbers which are divisible by 6 - Numbers which are divisible by 30
Total number of 4 digit numbers = 9999 - 999 = 9000
Number of 4 digit numbers divisible by 6 = 9000/6 = 1500
Number of 4 digit numbers divisible by 30 = 9000/30 = 300
Required numbers = 1500 - 300 = 1200.
Hence, option (c).