Given f(x) = x2 + log3x and g(y) = 2y + f(y), then the value of g(3) equals
Explanation:
Given, f(x) = x2 + log3x and g(y) = 2y + f(y),
∴ g(3) = 2 × 3 + f(3)
⇒ g(3) = 2 × 3 + 32 + log33
⇒ g(3) = 6 + 9 + 1 = 16
Hence, option (a).
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