If a% of a + b% of b = 2% of ab, then what percent of a is b?
Answer: D
Given: a% of a + b% of b = 2% of ab.
\( \frac{a^2}{100} + \frac{b^2}{100} = \frac{2ab}{100} \)
\( a^2 + b^2 - 2ab = 0 \), so \( (a-b)^2 = 0 \).
This gives a = b, so b is 100% of a.
Answer: 100%