# Algebra - Quadratic Equations - Previous Year CAT/MBA Questions

The best way to prepare for Algebra - Quadratic Equations is by going through the previous year **Algebra - Quadratic Equations XAT questions**.
Here we bring you all previous year Algebra - Quadratic Equations XAT questions along with detailed solutions.

Click here for previous year questions of other topics.

It would be best if you clear your concepts before you practice previous year Algebra - Quadratic Equations XAT questions.

To keep track of your progress of PYQs join our FREE CAT PYQ Course.

Join our Telegram Channel for CAT/MBA Preparation.

**XAT 2024 QADI | Algebra - Quadratic Equations XAT Question**

The roots of the polynomial P(x) = 2x^{3} - 11x^{2} + 17x + 6 are the radii of three concentric circles. The ratio of their area, when arranged from the largest to the smallest, is:

- (a)
6 : 2 : 1

- (b)
9 : 4 : 1

- (c)
16 : 6 : 3

- (d)
36 : 16 : 1

- (e)
None of the remaining options is correct.

Answer: Option D

To keep track of your progress of PYQs join our FREE CAT PYQ Course.

Join our Telegram Channel for CAT/MBA Preparation.

**Text Explanation** :

Workspace:

**XAT 2018 QADI | Algebra - Quadratic Equations XAT Question**

Two different quadratic equations have a common root. Let the three unique roots of the two equations be A, B and C - all of them are positive integers. If (A + B + C) = 41 and the product of the roots of one of the equations is 35, which of the following options is definitely correct?

- (a)
The common root is 29.

- (b)
The smallest among the roots is 1.

- (c)
One of the roots is 5.

- (d)
Product of the roots of the other equation is 5.

- (e)
All of the above are possible, but none are definitely correct.

Answer: Option C

To keep track of your progress of PYQs join our FREE CAT PYQ Course.

Join our Telegram Channel for CAT/MBA Preparation.

**Text Explanation** :

A, B and C are positive integers.

Let the common root is A.

∴ A × B = 35

This is possible when (A, B) is (1, 35) or (35, 1) or (5, 7) or (7, 5)

C = 41 – A - B

For each of these 4 possibilities value of C = 5 or 5 or 29 or 29

In each of these 4 possibilities, one of the roots is definitely 5.

Hence, option (c).

Workspace:

**XAT 2017 QADI | Algebra - Quadratic Equations XAT Question**

If x and y are real numbers, the least possible value of the expression 4(x - 2)^{2} + 4(y - 3)^{2} – 2(x - 3)^{2 }is:

- (a)
-8

- (b)
-4

- (c)
-2

- (d)
0

- (e)
2

Answer: Option B

To keep track of your progress of PYQs join our FREE CAT PYQ Course.

Join our Telegram Channel for CAT/MBA Preparation.

**Text Explanation** :

4(x – 2)^{2} + 4(y – 3)^{2} – 2(x – 3)^{2}

= 4(x^{2} + 4 – 4x) + 4(y – 3)^{2} – 2(x^{2} + 9 – 6x)

= 4(y – 3)^{2} + 2x^{2} – 4x – 2

Now, (y – 3)^{2} least value would be 0.

The least value of 2x^{2} – 4x – 2 would be at x = -(-4)/(2×2) = 1

The least value of 2x^{2} – 4x – 2 = 2(1)^{2} – 4(1) – 2 = -4

The least value of the expression would be = – 4.

Hence, option (b).

Workspace:

**XAT 2015 QA | Algebra - Quadratic Equations XAT Question**

Devanand’s house is 50 km West of Pradeep’s house. On Sunday morning, at 10 a.m., they leave their respective houses.

Under which of the following scenarios, the minimum distance between the two would be 40 km?

**Scenario I:** Devanand walks East at a constant speed of 3 km per hour and Pradeep walks South at a constant speed of 4 km per hour.

**Scenario II:** Devanand walks South at a constant speed of 3 km per hour and Pradeep walks East at a constant speed of 4 km per hour.

**Scenario III:** Devanand walks West at a constant speed of 4 km per hour and Pradeep walks East at a constant speed of 3 km per hour.

- (a)
Scenario I only

- (b)
Scenario II only

- (c)
Scenario III only

- (d)
Scenario I and II

- (e)
None of the above

Answer: Option A

To keep track of your progress of PYQs join our FREE CAT PYQ Course.

Join our Telegram Channel for CAT/MBA Preparation.

**Text Explanation** :

Scenario 1: Devanand walks East at a constant speed of 3 km per hour and Pradeep towards South at a constant speed of 4 km per hour,

Let the two walk for x hours.

Distance travelled by Devanand and Pradeep is 3x km and 4x km respectively.

Thus, we have

∴ (AP)^{2} + (CP)^{2} = (50 – 3*x*)^{2} + (4*x*)^{2} = 402

Solving this, we get *x* = 6

Thus, after 6 hours, the minimum distance between the two would be 40 km.

The distance between the two will increase in other two scenarios.

Hence, option (a).

Workspace:

## Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.