# LR - Series - Previous Year CAT/MBA Questions

The best way to prepare for LR - Series is by going through the previous year **LR - Series omet questions**.
Here we bring you all previous year LR - Series omet questions along with detailed solutions.

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It would be best if you clear your concepts before you practice previous year LR - Series omet questions.

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**CMAT 2024 Slot 1 LRDI | LR - Series omet Question**

Arrange the following words in a meaningful sequence and choose the most appropriate sequence from the given alternatives.

(A) Rain

(B) Monsoon

(C) Rescue

(D) Flood

(E) Shelter

(F) Relief

- (a)
(A), (B), (C), (D), (E), (F)

- (b)
(A), (B), (D), (E), (C), (F)

- (c)
(B), (A), (D), (C), (E), (F)

- (d)
(D), (A), (B), (C), (F), (E)

Answer: Option C

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**Text Explanation** :

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**SNAP 10th Dec 2023 Logical Reasoning Slot 1 (Memory Based) | LR - Series omet Question**

Find the next term of the series: 1, 2, 4, 7, 11, 16, 22, ___

- (a)
28

- (b)
27

- (c)
26

- (d)
29

Answer: Option D

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**Text Explanation** :

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**SNAP 10th Dec 2023 Logical Reasoning Slot 1 (Memory Based) | LR - Series omet Question**

Find the next term of the sequence: V^{2}U^{2}W, V^{2}U^{2}W^{2}, V^{2}U^{2}W^{3}, ___

- (a)
V

^{2}U^{2}W^{3} - (b)
V

^{2}U^{2}W^{4} - (c)
V

^{2}U^{2}W^{5} - (d)
None of these

Answer: Option B

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**Text Explanation** :

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**SNAP 10th Dec 2023 Logical Reasoning Slot 1 (Memory Based) | LR - Series omet Question**

Find the wrong term of the series and which number should replace it to make the sequence correct: 24, 34, 36, 51, 48, 68, 60, 85, 70, 102.

- (a)
70, 72

- (b)
60, 58

- (c)
68, 70

- (d)
48, 60

Answer: Option A

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**Text Explanation** :

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**SNAP 10th Dec 2023 Logical Reasoning Slot 1 (Memory Based) | LR - Series omet Question**

Find the next term of the series: 1, 3, 7, 13, 21, 31, ___

- (a)
41

- (b)
43

- (c)
45

- (d)
None of these

Answer: Option B

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**Text Explanation** :

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**SNAP 10th Dec 2023 Logical Reasoning Slot 1 (Memory Based) | LR - Series omet Question**

Find the missing term of the sequence:

Tue, Wed, Fri, Mon, ?, Wed

- (a)
Thursday

- (b)
Saturday

- (c)
Friday

- (d)
Sunday

Answer: Option C

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**Text Explanation** :

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**SNAP 10th Dec 2023 Logical Reasoning Slot 1 (Memory Based) | LR - Series omet Question**

Find the logically correct sequence

1. Pune

2. Aga Khan Palace

3. World

4. India

5. Maharashtra

- (a)
21543

- (b)
21453

- (c)
34521

- (d)
45321

Answer: Option A

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**Text Explanation** :

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**CMAT 2022 Logical Reasoning | LR - Series omet Question**

Complete the series; DIT, GMQ, KQM, PUH,____

- (a)
VYB

- (b)
UYB

- (c)
VXC

- (d)
TUJ

Answer: Option A

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**Text Explanation** :

Considering the first letters of each term.

There are 2 alphabets in between D and G (E and F).

There are 3 alphabets between G and K (H, I and J).

There are 4 alphabets between K and P (L, M, N, and O)

Hence, there will be 5 alphabets between P and the required letter. Thus, the required letter will be V (Q, R, S, T and U)

Considering the second letter of each term.

There are three alphabets between each of the second terms, I and M (J, K, L), M and Q (N, O, P), and Q and U (R, S, T).

Hence, there will be three terms between the required term and U, i.e., V, W, X. Thus, the required second term is Y.

Hence, option (a).

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**CMAT 2022 Logical Reasoning | LR - Series omet Question**

Complete the series; FAQ, AQF, ___, FAQ, AQF

- (a)
QAF

- (b)
QFA

- (c)
FQA

- (d)
AFQ

Answer: Option B

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**Text Explanation** :

From the 2nd term onwards,

1st letter of every term is 2nd letter of the previous term

2nd letter of every term is 3rd letter of the previous term

3rd letter of every term is 1st letter of the previous term

2nd term is AQF so as per the above logic third term will be QFA.

Hence, option (b).

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**CMAT 2022 Logical Reasoning | LR - Series omet Question**

Complete the sequence: 24, __, 48, 63

- (a)
35

- (b)
14

- (c)
37

- (d)
39

Answer: Option A

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**Text Explanation** :

All the terms are of the form

5^{2} - 1 = 24,

7^{2} - 1 = 48,

8^{2} - 1 = 63

∴ 6^{2}- 1 = 35

Hence, option (a).

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**IIFT 23 Dec 2021 LRDI | LR - Series omet Question**

Complete the following sequence:

5, 72, 412, 2658, __________?

- (a)
12772

- (b)
21264

- (c)
21512

- (d)
18876

Answer: Option C

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**Text Explanation** :

The series is in the form of 2na_{n} + 62 (n − 1), n > 1, where a_{1} = 5

For n = 2, a_{2} = 5 × 2 + 62 × 1 = 72

For n = 3, a_{3} = 72 × 4 + 62 × 2 = 412

For n = 4, a_{4} = 412 × 6 + 62 × 3 = 2658

For n = 5, a_{5} = 2658 × 8 + 62 × 4 = 21512

Thus the correct option is C.

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**IIFT 2019 LRDI | LR - Series omet Question**

**Complete the given sequence**

63, 215, 511, 999

- (a)
1330

- (b)
1727

- (c)
1335

- (d)
1735

Answer: Option B

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**Text Explanation** :

The logic for the Given sequjence is;

43 – 1 = 63

63 – 1 = 215

83 – 1 = 511

103 – 1 = 999

So, the next number in the sequence will be;

123 – 1 = 1727

Hence, option (b).

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**IIFT 2018 LR | LR - Series omet Question**

Find the value of X.

- (a)
299

- (b)
399

- (c)
298

- (d)
308

Answer: Option A

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**Text Explanation** :

The logic is 54 x 7 = (79 + X)

Thus, X = 378 – 79 = 299

Hence, option (a)

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**IIFT 2016 LRDI | LR - Series omet Question**

Insert the missing number

- (a)
35

- (b)
48

- (c)
72

- (d)
120

Answer: Option B

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**Text Explanation** :

Middle number = (difference between numbers of left column) × (sum of numbers of right column)

i.e. 80 = (15 – 5) × (2 + 6) = (10) × (8) and 65 = (9 – 4) × (7 + 6) = (5) × (13)

∴ ? = (13 – 11) × (16 + 8) = 2 × 24 = 48

Hence, option (b).

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**IIFT 2016 LRDI | LR - Series omet Question**

In the following question, one term in the number series is wrong. Find out the wrong term.

10, 26, 74, 218, 654, 1946, 5834

- (a)
654

- (b)
26

- (c)
1946

- (d)
218

Answer: Option A

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**Text Explanation** :

The logic is: given term = (previous term) × 3 – 4

This pattern is broken for 654 i.e.(218 × 3) – 4 = 650

Hence, the wrong term is 654.

Hence, option (a).

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**IIFT 2015 LRDI | LR - Series omet Question**

Based on the number series given, fill in the missing number.18, 37, 76, 155, ________, 633, 1272

- (a)
322

- (b)
314

- (c)
341

- (d)
250

Answer: Option B

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**Text Explanation** :

The Pattern here is,

18 × 2 + 1 = 37,

37 × 2 + 2 = 76,

76 × 2 + 3 = 155,

So,

155 × 2 + 4 = 314,

314 × 2 + 5 = 633,

633 × 2 + 6 = 1272,

Hence, option (b).

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**IIFT 2014 LRDI | LR - Series omet Question**

**Complete the series:**EPFS, GPHS, IPJS, _________, MPNS

- (a)
OPLS

- (b)
KPMS

- (c)
LMPS

- (d)
KPLS

Answer: Option D

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**Text Explanation** :

The 2nd and 4th alphabets are constant.

For 1st letter: E + 2 = G, G + 2 = I, I + 2 = K, K + 2 = M

Similarly, 3rd letter: F + 2 = H, H + 2 = J, J + 2 = L, L + 2 = N

Hence, option (d).

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**IIFT 2013 LRDI | LR - Series omet Question**

**Select the correct option to fill in the blank space/s**

c_bba_cab_ac_ab_ac

- (a)
b, c, b, a, c

- (b)
c, a, b, c, b

- (c)
a, c, c, b, c

- (d)
a, c, b, c, b

Answer: Option D

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**Text Explanation** :

Substitute the options into the blanks and try to find whether a sequence is formed. The sequence ‘cabbac’ repeats itself.

Hence, option (d).

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**IIFT 2013 LRDI | LR - Series omet Question**

**Select the correct option to fill in the blank space/s**

B_{2}CD, _____, BCD_{4}, _____, BC_{6}D

- (a)
BC

_{3}D; B_{5}CD - (b)
BC

_{2}D; BC_{3}D - (c)
BC

_{3}D; B_{3}CD - (d)
BC

_{3}D; BC_{5}D

Answer: Option A

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**Text Explanation** :

The subscript in the terms follows the pattern: 2 _ 4 _ 6.

Hence, the subscript in the missing terms is 3 and 5 respectively.

Also, the position of the subscript follows the pattern B _ D _ C. Hence, it should be with the letters C and B respectively in the missing terms.

Hence, option (a).

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**IIFT 2013 LRDI | LR - Series omet Question**

**Select the correct option to fill in the blank space/s**

P3, M8, ____, G24, D35

- (a)
K15

- (b)
J13

- (c)
I13

- (d)
J15

Answer: Option D

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**Text Explanation** :

There is a gap of two letters between the given letters. Thus, the letter to be filled in the blank space would be ‘J’. Second difference between the numbers is common. Therefore, the number would be 8 + 7 = 15.

Hence, option (d).

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**IIFT 2012 LRDI | LR - Series omet Question**

In the following series, what numbers should replace the question marks?

–1, 0, 1, 0, 2, 4, 1, 6, 9, 2, 12, 16, ? ? ?

- (a)
11, 18, 27

- (b)
–1, 0, 3

- (c)
3, 20, 25

- (d)
Cannot be ascertained

Answer: Option C

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**Text Explanation** :

This series contains three series in itself.

Series 1 (T_{1}, T_{4}, T_{7}, T_{10}): –1, 0, 1, 2 (AP with a common difference of +1)

Series 2 (T_{2}, T_{5}, T_{8}, T_{11}): 0, 2, 6, 12 (Differences between two terms increase by 2)

Series 3 (T_{3}, T_{6}, T_{9}, T_{12}): 1, 4, 9, 16 (Squares of consecutive numbers)

The next three numbers will thus be 3, 20 and 25.

Hence, option (c).

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**IIFT 2012 LRDI | LR - Series omet Question**

If IQS : LNV, then JRM : ?

- (a)
OKS

- (b)
MOP

- (c)
NIP

- (d)
MOQ

Answer: Option B

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**Text Explanation** :

Considering the positions of the letters in the alphabet,

I + 3 = L, Q – 3 = N and S + 3 = V

So J + 3 = M, R – 3 = O and M + 3 = P.

Hence the correct analogy is JRM : MOP

Hence, option (b).

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**IIFT 2012 LRDI | LR - Series omet Question**

Find the missing alphabet.

- (a)
Y

- (b)
O

- (c)
D

- (d)
G

Answer: Option C

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**Text Explanation** :

The position numbers of the letters in the alphabet are as follows:

We can see that in each column the number in the third row is the product of the numbers in the first and second rows.

Thus the missing number is 20/5 = 4

The fourth letter of the alphabet is D.

Hence, option (c).

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**IIFT 2012 LRDI | LR - Series omet Question**

Which four bits can be joined together to form two words that have opposite meanings?

ERT, UCE, DES, END, EXP, EAR, AND, SIP, RED, GOS

1 2 3 4 5 6 7 8 9 10

- (a)
2, 5, 7, 9

- (b)
1, 3, 8, 10

- (c)
1, 5, 8, 10

- (d)
2, 4, 7, 8

Answer: Option A

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**Text Explanation** :

Consider option 1 – 2,5,7,9.

If we join 2 and 9, we get REDUCE and if join 5 and 7, we get EXPAND. Reduce and Expand are antonyms.

Hence, option (a).

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**IIFT 2011 LR | LR - Series omet Question**

**In each of the following letter series, some of the letters are missing, which are given below it. Choose the correct alternative.**

D_F_DEE_D_EF_DE_F

- (a)
EFFDED

- (b)
EFFDDF

- (c)
EFFDFE

- (d)
None of the above

Answer: Option C

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**Text Explanation** :

If we split the alphabets in a group of 3 we get following arrangement:

D__F | __DE | E__D | __EF | __DE | __F

Now, if we put option 3, we get:

DEF | FDE | EFD | DEF | FDE | EF

If we see the pattern it is consistent in the sense that the third alphabet in each subset is the first alphabet in the next subset and the order is cyclic. (D, E, F or F, D, E or E, F, D).

Hence, option (c).

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