LR - Series - Previous Year CAT/MBA Questions
You can practice all previous year OMET questions from the topic LR - Series. This will help you understand the type of questions asked in OMET.
It would be best if you clear your concepts before you practice previous year OMET questions.
1. IIFT 2019 LRDI | LR - Series
Complete the given sequence
63, 215, 511, 999
- A.
1330
- B.
1727
- C.
1335
- D.
1735
Answer: Option
B
Explanation :
The logic for the Given sequjence is;
43 – 1 = 63
63 – 1 = 215
83 – 1 = 511
103 – 1 = 999
So, the next number in the sequence will be;
123 – 1 = 1727
Hence, option 2.
2. IIFT 2018 LR | LR - Series
Find the value of X.
- A.
299
- B.
399
- C.
298
- D.
308
Answer: Option
A
Explanation :
The logic is 54 x 7 = (79 + X)
Thus, X = 378 – 79 = 299
Hence, option 1
3. IIFT 2016 LRDI | LR - Series
Insert the missing number
Answer: Option
B
Explanation :
Middle number = (difference between numbers of left column) × (sum of numbers of right column)
i.e. 80 = (15 – 5) × (2 + 6) = (10) × (8) and 65 = (9 – 4) × (7 + 6) = (5) × (13)
∴ ? = (13 – 11) × (16 + 8) = 2 × 24 = 48
Hence, option 2.
4. IIFT 2016 LRDI | LR - Series
In the following question, one term in the number series is wrong. Find out the wrong term.
10, 26, 74, 218, 654, 1946, 5834
- A.
654
- B.
26
- C.
1946
- D.
218
Answer: Option
A
Explanation :
The logic is: given term = (previous term) × 3 – 4
This pattern is broken for 654 i.e.(218 × 3) – 4 = 650
Hence, the wrong term is 654.
Hence, option 1.
5. IIFT 2015 LRDI | LR - Series
Based on the number series given, fill in the missing number.18, 37, 76, 155, ________, 633, 1272
- A.
322
- B.
314
- C.
341
- D.
250
Answer: Option
B
Explanation :
The Pattern here is,
18 × 2 + 1 = 37,
37 × 2 + 2 = 76,
76 × 2 + 3 = 155,
So,
155 × 2 + 4 = 314,
314 × 2 + 5 = 633,
633 × 2 + 6 = 1272,
Hence, option 2.
6. IIFT 2014 LRDI | LR - Series
Complete the series:EPFS, GPHS, IPJS, _________, MPNS
- A.
OPLS
- B.
KPMS
- C.
LMPS
- D.
KPLS
Answer: Option
D
Explanation :
The 2nd and 4th alphabets are constant.
For 1st letter: E + 2 = G, G + 2 = I, I + 2 = K, K + 2 = M
Similarly, 3rd letter: F + 2 = H, H + 2 = J, J + 2 = L, L + 2 = N
Hence, option 4.
7. IIFT 2013 LRDI | LR - Series
Select the correct option to fill in the blank space/s
c_bba_cab_ac_ab_ac
- A.
b, c, b, a, c
- B.
c, a, b, c, b
- C.
a, c, c, b, c
- D.
a, c, b, c, b
Answer: Option
D
Explanation :
Substitute the options into the blanks and try to find whether a sequence is formed. The sequence ‘cabbac’ repeats itself.
Hence, option 4.
8. IIFT 2013 LRDI | LR - Series
Select the correct option to fill in the blank space/s
B2CD, _____, BCD4, _____, BC6D
- A.
BC3D; B5CD
- B.
BC2D; BC3D
- C.
BC3D; B3CD
- D.
BC3D; BC5D
Answer: Option
A
Explanation :
The subscript in the terms follows the pattern: 2 _ 4 _ 6.
Hence, the subscript in the missing terms is 3 and 5 respectively.
Also, the position of the subscript follows the pattern B _ D _ C. Hence, it should be with the letters C and B respectively in the missing terms.
Hence, option 1.
9. IIFT 2013 LRDI | LR - Series
Select the correct option to fill in the blank space/s
P3, M8, ____, G24, D35
- A.
K15
- B.
J13
- C.
I13
- D.
J15
Answer: Option
D
Explanation :
There is a gap of two letters between the given letters. Thus, the letter to be filled in the blank space would be ‘J’. Second difference between the numbers is common. Therefore, the number would be 8 + 7 = 15.
Hence, option 4.
10. IIFT 2012 LRDI | LR - Series
In the following series, what numbers should replace the question marks?
–1, 0, 1, 0, 2, 4, 1, 6, 9, 2, 12, 16, ? ? ?
- A.
11, 18, 27
- B.
–1, 0, 3
- C.
3, 20, 25
- D.
Cannot be ascertained
Answer: Option
C
Explanation :
This series contains three series in itself.
Series 1 (T1, T4, T7, T10): –1, 0, 1, 2 (AP with a common difference of +1)
Series 2 (T2, T5, T8, T11): 0, 2, 6, 12 (Differences between two terms increase by 2)
Series 3 (T3, T6, T9, T12): 1, 4, 9, 16 (Squares of consecutive numbers)
The next three numbers will thus be 3, 20 and 25.
Hence, option 3.
11. IIFT 2012 LRDI | LR - Series
If IQS : LNV, then JRM : ?
- A.
OKS
- B.
MOP
- C.
NIP
- D.
MOQ
Answer: Option
B
Explanation :
Considering the positions of the letters in the alphabet,
I + 3 = L, Q – 3 = N and S + 3 = V
So J + 3 = M, R – 3 = O and M + 3 = P.
Hence the correct analogy is JRM : MOP
Hence, option 2.
12. IIFT 2012 LRDI | LR - Series
Find the missing alphabet.
Answer: Option
C
Explanation :
The position numbers of the letters in the alphabet are as follows:
We can see that in each column the number in the third row is the product of the numbers in the first and second rows.
Thus the missing number is 20/5 = 4
The fourth letter of the alphabet is D.
Hence, option 3.
13. IIFT 2012 LRDI | LR - Series
Which four bits can be joined together to form two words that have opposite meanings?
ERT, UCE, DES, END, EXP, EAR, AND, SIP, RED, GOS
1 2 3 4 5 6 7 8 9 10
- A.
2, 5, 7, 9
- B.
1, 3, 8, 10
- C.
1, 5, 8, 10
- D.
2, 4, 7, 8
Answer: Option
A
Explanation :
Consider option 1 – 2,5,7,9.
If we join 2 and 9, we get REDUCE and if join 5 and 7, we get EXPAND. Reduce and Expand are antonyms.
Hence, option 1.
14. IIFT 2011 LR | LR - Series
In each of the following letter series, some of the letters are missing, which are given below it. Choose the correct alternative.
D_F_DEE_D_EF_DE_F
- A.
EFFDED
- B.
EFFDDF
- C.
EFFDFE
- D.
None of the above
Answer: Option
C
Explanation :
If we split the alphabets in a group of 3 we get following arrangement:
D__F | __DE | E__D | __EF | __DE | __F
Now, if we put option 3, we get:
DEF | FDE | EFD | DEF | FDE | EF
If we see the pattern it is consistent in the sense that the third alphabet in each subset is the first alphabet in the next subset and the order is cyclic. (D, E, F or F, D, E or E, F, D).
Hence, option 3.
15. IIFT 2011 LR | LR - Series
In each of the following letter series, some of the letters are missing, which are given below it. Choose the correct alternative.
OPO_QOPQ_RQPO_POR_O
- A.
APRQO
- B.
QPORO
- C.
QPROO
- D.
None of the above
Answer: Option
D
Explanation :
Let us put the options in the blanks and consider the patterns one by one.
Option 1: AOPOPQOPQRRQPOQPOROO
Here, having A is not logical. Hence this option is eliminated.
Option 2: QOPOPQOPQORQPORPOROO
There is no logical pattern which is logically consistent with this option. Even if we divide in the groups of 3, 4, 5 we do not get any pattern that is logical.
Option 3: QOPOPQOPQRRQPOOPOROO
There is no pattern which is logically consistent with this option. Even if we divide in the groups of 3, 4, 5 we do not get any pattern that is logical.
Hence, option 4.
16. IIFT 2010 LRDI | LR - Series
How many ‘zeroes’ are there in the following sequence which are immediately preceded by a nine but not immediately followed by seven?
7090070890702030045703907
- A.
One
- B.
Two
- C.
Three
- D.
Four
Answer: Option
A
Explanation :
Consider the given sequence 7090070890702030045703907
There is only one zero that is immediately preceded by a nine and is not immediately followed by seven.
Hence, option 1.
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