# LR - Logical Connectives - Previous Year CAT/MBA Questions

You can practice all previous year OMET questions from the topic LR - Logical Connectives. This will help you understand the type of questions asked in OMET. It would be best if you clear your concepts before you practice previous year OMET questions.

**Answer the following question based on the information given below.**

Richie invites three of his friends Sunny, Pinky, and Nancy for his birthday party organized at his home. As the party goes on till late in the night, Sunny, Pinky, and Nancy choose to stay at Richie's house. Being good friends they usually stay back at each other's house. Each of them including Richie stay either in the room painted blue or in the painted purple. They have adequate number of rooms of both colours. The preferences which need to be fulfilled are:

- If sunny stays in the room painted purple, then Pinky and Richie stay in the same room as Nancy.
- If Pinky stays in the room painted purple, then Sunny stays in the room in which Nancy and Richie don't stay.
- If Nancy stays in the room painted blue, then Sunny and Richie stay in the room which Pinky has chosen.
- If Richie stays in the room painted Blue then Sunny and Pinky do not stay in the same room as Nancy.

**IIFT 2018 LR | LR - Logical Connectives**

Under all possible combinations which of the two friends will always have their room colours unchanged.

- A.
Richie & Sunny

- B.
Pinky & Richie

- C.
Nancy & Sunny

- D.
Nancy & Pinky

Answer: Option C

**Explanation** :

The following table can be made using the given 4 conditions :

Case 2a, 3a and 4a violates condition I, so these 3 cases are invalid.

Case 1a, 1b violates condition iii, so these cases are invalid.

Case 3b violates condition iv, so this case is invalid.

Finally we have the following two cases:

Nancy & Sunny.

Hence, option 3.

Workspace:

**IIFT 2018 LR | LR - Logical Connectives**

If Richie chose to stay in the room painted blue, then in which room does Pinky stay?

- A.
Purple

- B.
Blue

- C.
Data Inadequate

- D.
None of the above

Answer: Option A

**Explanation** :

The following table can be made using the given 4 conditions :

Case 2a, 3a and 4a violates condition I, so these 3 cases are invalid.

Case 1a, 1b violates condition iii, so these cases are invalid.

Case 3b violates condition iv, so this case is invalid.

Finally we have the following two cases:

Purple

Hence, option 1.

Workspace:

**IIFT 2018 LR | LR - Logical Connectives**

If Pinky does not like to stay in the blue painted room, then where will Sunny stay?

- A.
Blue

- B.
Purple

- C.
Data Inadequate

- D.
None of the above

Answer: Option A

**Explanation** :

The following table can be made using the given 4 conditions :

Case 2a, 3a and 4a violates condition I, so these 3 cases are invalid.

Case 1a, 1b violates condition iii, so these cases are invalid.

Case 3b violates condition iv, so this case is invalid.

Finally we have the following two cases:

Blue

Hence, option 1.

Workspace:

**IIFT 2015 LRDI | LR - Logical Connectives**

Based on the given statement, choose the right conclusion:‘If the breakfast doesn’t have eggs, I will not go for a walk and will not have lunch.’

- A.
If I went for a walk and didn’t have lunch, the breakfast didn’t have eggs.

- B.
If I went for a walk or I had lunch, the breakfast had eggs.

- C.
If I went for a walk or I had no lunch, the breakfast had eggs.

- D.
If I didn’t go for a walk and had lunch, the breakfast had eggs.

Answer: Option B

**Explanation** :

Let,

A = The breakfast doesn't have eggs

B = I will not go for a walk and will not have lunch.

From the logical deductions,

AB = ~B~A

Also, and is replaced by or and vice versa.

So,

~A = The breakfast has eggs.

~B = I will go for a walk or will have lunch.

So, we get,

~B~A = I will go for a walk or will have lunch, the breakfast has eggs.

Hence, option 2.

Workspace:

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