# LR - Directions - Previous Year CAT/MBA Questions

You can practice all previous year OMET questions from the topic LR - Directions. This will help you understand the type of questions asked in OMET. It would be best if you clear your concepts before you practice previous year OMET questions.

**Answer the following question based on the information given below.**

On a cricket ground, five players - A, B, C, D and E are standing as described below facing the North

- B is 75 metres to the right of D
- A is 95 metres to the south of B
- C is 45 metres to the west of D
- E is 110 metres to the north of A

**IIFT 2017 LR | LR - Directions**

Who is to the north-east of the player who is to the left of B?

- A.
A

- B.
C

- C.
Either A or C

- D.
None of the above

Answer: Option D

**Explanation** :

The position of the players can be plotted as shown below:

D and C are to the left of B; and E is to their north-east.

Hence, option 4.

Workspace:

**IIFT 2017 LR | LR - Directions**

If a player walks from C, meets D followed by B, then A and finally E, how many metres has the player walked if he has travelled the straight distance all through?

- A.
185

- B.
135

- C.
230

- D.
325

Answer: Option D

**Explanation** :

The position of the players can be plotted as shown below:

Total distance = 45 + 75 + 95 + 95 + 15 = 325 metres.

Hence, option 4.

Workspace:

**IIFT 2015 LRDI | LR - Directions**

Alex walks 1 mile towards East and then he turns towards South and walks further 5 miles. After that he turns East and walks 2 miles further. Finally he turns to his North and walks 9 miles. How far is he from the starting point?

- A.
25 miles

- B.
2 miles

- C.
5 miles

- D.
4 miles

Answer: Option C

**Explanation** :

From the figure, the final position is E and the starting point is D.

Distance DT = Distance DF + Distance FT

= Distance DF + Distance HP

= 1 + 2

= 3 miles.

Distance ET = DistanceEP – Distance TP

= Distance EP – Distance FH

= 9 – 5

= 4 miles

From the figure, the distance between starting point and the end point is

(DE)2 = 32 + 42

= 9 + 16

= 25

DE = 5 miles

Hence, option 3.

Workspace:

**XAT 2015 QA | LR - Directions**

Devanand’s house is 50 km West of Pradeep’s house. On Sunday morning, at 10 a.m., they leave their respective houses.

Under which of the following scenarios, the minimum distance between the two would be 40 km?

**Scenario I:** Devanand walks East at a constant speed of 3 km per hour and Pradeep walks South at a constant speed of 4 km per hour.

**Scenario II:** Devanand walks South at a constant speed of 3 km per hour and Pradeep walks East at a constant speed of 4 km per hour.

**Scenario III:** Devanand walks West at a constant speed of 4 km per hour and Pradeep walks East at a constant speed of 3 km per hour.

- A.
Scenario I only

- B.
Scenario II only

- C.
Scenario III only

- D.
Scenario I and II

- E.
None of the above

Answer: Option A

**Explanation** :

Scenario 1: Devanand walks East at a constant speed of 3 km per hour and Pradeep towards South at a constant speed of 4 km per hour,

Let the two walk for x hours.

Distance travelled by Devanand and Pradeep is 3x km and 4x km respectively.

Thus, we have

∴ (AP)^{2} + (CP)^{2} = (50 – 3*x*)^{2} + (4*x*)^{2} = 402

Solving this, we get *x* = 6

Thus, after 6 hours, the minimum distance between the two would be 40 km.

The distance between the two will increase in other two scenarios.

Hence, option 1.

Workspace:

**XAT 2012 QA | LR - Directions**

Shyam, a fertilizer salesman, sells directly to farmers. He visits two villages A and B. Shyam starts from A, and travels 50 meters to the East, then 50 meters North-East at exactly 45° to his earlier direction, and then another 50 meters East to reach village B. If the shortest distance between villages A and B is in the form of $a\sqrt{b+\sqrt{c}}$ meters, find the value of a + b + c.

- A.
52

- B.
54

- C.
58

- D.
59

- E.
None of the above

Answer: Option E

**Explanation** :

Total distance travelled by Shyam is;

$50+50+\frac{50}{\sqrt{2}}$ km towards east, and $\frac{50}{\sqrt{2}}$ km towards north

Hence, smallest distance, say d, between village A and Village B is;

$d=\sqrt{({(100+25\sqrt{2})}^{2}+{\left(25\sqrt{2}\right)}^{2})}$

Hence, ${d}^{2}={(100+25\sqrt{2})}^{2}+{\left(25\sqrt{2}\right)}^{2}={a}^{2}(b+\sqrt{c})$

But, ${(100+25\sqrt{2})}^{2}+{\left(25\sqrt{2}\right)}^{2}=2500(5+2\sqrt{2})$

$=2500(5+\sqrt{8})$

Hence, *a*^{2} = 2500, *b* = 5 and *c* = 8

Hence, *a* + *b* + *c* = 50 + 5 + 8 = 63

Hence, option 5.

Workspace:

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