DI - Tables & Graphs - Previous Year CAT/MBA Questions
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Read the following passage:
Four colleagues A,B,C and D during lunch time which is from 1:00 - 1:30 pm on a given day go for a walkthrough 2 different routes i.e. they exit from one gate and enter from the other one. A straight path, within the office, connects Gates 1 and 2. A and B exit from Gate 1 and enter from Gate 2, and again move towards Gate 1 using the straight path; while C and D exit from Gate 2 and enter from Gate 1, and again move towards Gate 2 using the straight path. The routes are in clockwise direction i.e. Gate1 to Gate 2 aperson can only walk in clockwise direction and similarly from Gate 2 to Gate 1. It takes 4 minutes to walkfrom Gate 1 exit to Gate 2 entrance and 6 minutes to walk from Gate 2 exit to Gate 1 entrance. The time taken to walk from Gate 1 to Gate 2 and vice versa within the office is 1 minute.
Initially, the colleagues leave at a gap of 2 minutes each in the order of B, A, C and D during lunch time. Each person starts thenext round of walk immediately after completing the first round.
If A leaves from Gate 1 at 1:02 pm, when will A leave for his third round?
- (a)
1:16 pm
- (b)
1:12 pm
- (c)
1:18 pm
- (d)
1:24 pm
Answer: Option B
Text Explanation :
Since A is moving from Gate 1 to Gate 2 and then coming back to Gate 1, the total time for completion of one round will be 5 minutes.
After completion of 2 rounds, i.e., after 10 minutes, A will leave for the third round. Thus, the correct answer is B.
Workspace:
If D leaves Gate 2 at 1:15 pm, following the same sequence as stated in the passage, thenwhich of the two colleagues will meet at Gate 2 before 1:30 pm?
- (a)
A and B
- (b)
C and A
- (c)
D and A
- (d)
B and D
Answer: Option B
Text Explanation :
Workspace:
Read the following passage:
On a picnic trip of a company, 3 hotels Trident, Hilton and Park were booked for 90 employees. 6 of the employees were willing to stay at any hotel. 12 wanted to stay in only Trident. 18 wanted to stay in only Park. Only Hilton had two times the employees as there were in Trident and Park only. Only Hilton and Parkhad three less than only Trident and Hilton. Also not more than 7 employees can stay in only Trident andHilton.
How many employees can stay in Hilton?
- (a)
47
- (b)
44
- (c)
45
- (d)
46
Answer: Option C
Text Explanation :
Now, total employees in Hilton = 2X + 2Y + 9 = 36 + 9 = 45
Thus, the correct option is C
Workspace:
How many employees can stay in Trident and Hilton only?
- (a)
4
- (b)
6
- (c)
7
- (d)
5
Answer: Option B
Text Explanation :
The number of employees in Trident and Hilton will be Y + 3 = 6.
Thus, the correct answer will be B.
Workspace:
The pie charts given below depict the percentage productionbreakup of 4 crops viz maize, corn, soyabean and wheat in the world and USArespectively. Assume that the total world production of these crops in a given year is160 million tonnes.
In all the questions, 'ROW' means rest of the world other than USA.
Given that USA accounts for 20 percent of the total production of soyabean in the world then what percentage of the total food crops production of the world is accounted by USA?
- (a)
12 percent
- (b)
24 percent
- (c)
28 percent
- (d)
30 percent
Answer: Option C
Text Explanation :
Given: 20% of total soyabean production of the world is from USA
Thus, Let the total world production of crops be P.
Thus, USA's production of soyabean = 0.2 x 0.35 x P = 0.07P = 7% of the total productions of crops.
Soyabean productions consitutes 25% of the total crop production in the USA.
Thus, percentage of total crop production accounted by the USA = = 28%
Hence, the answer is option C.
Workspace:
Assume that the total production of maize in the USA is 3 million tonnes. Calculate the percentage (approximately) of the total production of food crops in the world accounted by the USA?
- (a)
3.55 percent
- (b)
4.68 percent
- (c)
5.75 percent
- (d)
7.82 percent
Answer: Option B
Text Explanation :
The total production of maize in the USA is 3 million tonnes and maize constitutes 40% of the total production of the USA.
Thus, total crop production in the USA = = 7 million tonnes.
Thus, the percentage of the total production of crops in the world accounted for by the USA = = 4.68%
Hence, the answer is option B.
Workspace:
If the ratio of production of wheat in USA and ROW is 1:6, then(approximately) what percentage of total food crop production of the ROW is accounted by wheat?
- (a)
5 percent
- (b)
8 percent
- (c)
12 percent
- (d)
15 percent
Answer: Option D
Text Explanation :
Total wheat production of the world = 15% of the total crop production of the world
= 15% (Crop production of the USA + Crop production of ROW)
=15%(USA production) + 15%(ROW crop production) ...(1)
To find the percentage of crop production of ROW accounted by wheat, we have to remove the wheat production of the USA.
Wheat production of the USA = 15% (USA production) ...(2)
Thus, the total wheat production of the ROW = 15%(ROW crop production)
Thus, wheat accounts for 15% of the total crop production of the ROW.
Hence, the answer is option D.
Alternately,
Since the wheat accounts for 15% of the total production of the World and the USA, it will also account for the 15% of the total crop production of the ROW.
Workspace:
USA produces 20 percent lesser corn than ROW, find the production ofsoyabean in USA?
- (a)
14.35 million tonnes
- (b)
8.75 million tonnes
- (c)
12.25 million tonnes
- (d)
17.75 million tonnes
Answer: Option D
Text Explanation :
Let the total production of crops in the USA, World and ROW be denoted by U, W and R, respectively.
Thus, 0.2(U) = 0.8[0.2W - 0.2U]
0.36U = 0.16W
U = W
Thus, production of soybean in the USA = 0.25U = 0.25 x W = 0.25 × × 160 = 17.75 million tonnes.
Hence, the answer is option D.
Workspace:
Refer to the following line charts and solve the questions based on them. The line charts given below give the expenditure and income of ABC Ltd. Which produces and sells only two variants of its rice - Basmati rice and Parmal rice.
The total profit of ABC Ltd. is highest in which of the following years?
- (a)
2007
- (b)
2009
- (c)
2012
- (d)
2004
Answer: Option B
Text Explanation :
Option A: Profits for 2007 = 1120 - 360 = 760
Option B: Profits for 2009 = 1420 - 310 = 1110
Option C: Profits for 2012 = 1220 - 560 = 660
Option D: Profits for 2004 = 920 - 460 = 460
Thus, the maximum profit is in the year 2009.
Hence, the answer is option B.
Workspace:
Calculate the number of years during 2005 to 2013 for atleast one of thetwo rice when income and expenditure did not follow the same trend (i.e both incomeand expenditure did not increase or decrease simultaneously compared to theprevious year)?
- (a)
5
- (b)
6
- (c)
8
- (d)
9
Answer: Option C
Text Explanation :
We have to count the years in which at least one of the rice's income and expenditure shows an opposite trend.
2005: Parmal rice has an opposite trend.
2006: None of the rice has opposite trends.
2007: Basmati rice has an opposite trend.
2008: Basmati rice has an opposite trend.
2009: Both the rice show an opposite trend.
2010: Both the rice show an opposite trend.
2011: Both the rice show an opposite trend.
2012: Basmati rice has an opposite trend.
2013: Basmati rice has an opposite trend.
Thus, all the years except 2008 have at least one rice showing an opposite trend in income and expenditure.
Thus, there are a total of 8 years.
Hence, the answer is option C.
Workspace:
The percentage annual increase in the income of Basmati rice is highest inwhich of the following years?
- (a)
2005
- (b)
2007
- (c)
2009
- (d)
2012
Answer: Option B
Text Explanation :
Option A: For 2005 = × 100 = = 17.85%
Option B: For 2007 = × 100 = = 43.47%
Option C: For 2009 = × 100 = = 35.71%
Option D: For 2012 = × 100 = = 17.85%
Hence, the answer is option B.
Workspace:
In which year the annual percentage decrease in the profit of parmal rice ismaximum as compared to that of the previous year?
- (a)
2009
- (b)
2010
- (c)
2011
- (d)
2013
Answer: Option C
Text Explanation :
Profit for 2008 = 330
Profit for 2009 = 530
Profit for 2010 = 280
Profit for 2011 = 80
Profit for 2012 = 230
Profit for 2013 = 230
From the above trend, we can observe that the maximum decrease is in the year 2011.
Hence, the answer is option C.
Workspace:
The graph below depicts the crime cases registered against foreigners in different countries in a given year. The crime cases are classified into three categories: Murder cases, theft cases and other cases. The data for nine countries are shown in the figure below.
These nine countries belong to the top ten countries in terms of the total number of cases registered. The tenth country is Malaysia, where only 523 theft cases were registered.
The table below shows the rank of the ten countries in terms of the number of cases registered in each of the three categories of crimes. If two countries are assigned rank2nd, then for any given crime, 3rd rank cannot be assigned to any country.
The rank of China in the murder cases category is?
- (a)
2nd
- (b)
5th
- (c)
7th
- (d)
8th
Answer: Option B
Text Explanation :
The rank of China in murder cases is 5.
Answer is option B.
Workspace:
In the top two countries on the basis of total registered cases, the approximate ratio of total number of murder cases to total number of theft cases is
- (a)
1 : 6
- (b)
1 : 7
- (c)
1 : 9
- (d)
1 : 4
Answer: Option C
Text Explanation :
The sum of murder cases in top two countries = 0 + 65 = 65
The sum of theft cases in top two countries = 523 + 40 = 563
Ratio = 65:563 = 1 : 8.66 1 : 9
Answer is option C.
Workspace:
Which of the following is correct about the ranks of countries in the other crimes category?
i) USA: 7
ii) Russia: 3
- (a)
Only (i) is correct
- (b)
Only (ii) is correct
- (c)
Both (i) and (ii) are correct
- (d)
Both (i) and (ii) are incorrect
Answer: Option C
Text Explanation :
The rank of USA in other crimes is 7 and the rank of Russia in other crimes is 3. Therefore, both (i) and (ii) are correct.
Answer is option C.
Workspace:
The sum of the ranks of Pakistan in the three categories of crimes is?
- (a)
4
- (b)
7
- (c)
5
- (d)
10
Answer: Option C
Text Explanation :
The sum of ranks of Pakistan in three categories = 1 + 3 + 1 = 5
Answer is option C.
Workspace:
The following graph provides data about the refrigerators and television sets manufactured by XYZ company in 8 days - day1 to day8.
However, on each day after quality check (QC) some products were found to be defective. The attached bar chart provides data about aggregate number of refrigerators and televisions manufactured by the company and the number of refrigerators found defective after QC on each day of the given eight days.
All the televisions and refrigerators which cleared the QC were packed for selling.
The bar chart given below provides information about the fraction of the number of televisions found defective to number of televisions which cleared the QC.
If the number of televisions which cleared the quality check (QC) on each of the given eight days is same, then at least how many refrigerators cleared the QC on day 3?
- (a)
20
- (b)
30
- (c)
25
- (d)
40
Answer: Option B
Text Explanation :
T-QC is same for all the days, then they should be in the form of 80k. LCM(4,8,2,5,10,16,5)
T-total on day 3 = 90k
T-total should be maximum to find the minimum value of refrigerators cleared QC.
T-total maximum = 270
Number of refrigerators = 400 - 270 = 130
R-QC = R-total - R-defective = 130 - 100 = 30
Answer is option B.
Workspace:
Which of the following can be the ratio of number of televisions and refrigerators which cleared the quality check on day1?
- (a)
1 : 4
- (b)
1 : 5
- (c)
1 : 6
- (d)
1 : 7
Answer: Option D
Text Explanation :
The number of televisions which cleared quality check on day 1 = 4a
The number of refrigerators which cleared quality check on day 1 = 800 - 7a - 100 = 700 - 7a
Ratio =
Only option D satisfies the above equation.
The answer is option D
Workspace:
Given that the number of televisions which cleared the quality check on each of the eight days is equal to 'X', then how many distinct values of X are possible?
- (a)
2
- (b)
3
- (c)
4
- (d)
5
Answer: Option B
Text Explanation :
X = 80k which can take only 3 values, i.e. 80, 160 and 240
Answer is option B.
Workspace:
Read the following passage:
Ten teams have submitted their nominations for a reputed Hackathon. They were first divided in two groups of 5 teams each: Ghost Riders to The Capitalists (group 1); and Team Intelligence to Dr Bigbull (group 2). In the competition, each team from one group had to pitch their idea against the each team from another group. For example Ghost Riders will have to pitch their idea against each team in group 2. The following table gives partial information about the final scoresheet at the end of the competition:
Note: * To be read as “Tech Pirates” lost the idea presentation round against “Evil Masterminds”.
For group 1 - The total points earned by each teams have been given in the last column e.g. Ghost Rider has scored 7 points overall.
For group 2 - The total points earned by each teams have been given in the last row e.g. Team Intelligence has scored 12 points overall.
In addition to this, the golden Hawks did not lose the presentation round against The Think Tank.
Point rule:
(i) If a team Wins, the winning team will get 5 points;
(ii) If there is a tie, both teams will get 2 points each; and
(iii) If a team lost the match, the losing team will get 0 points.
What was the result of presentation round between The Think Tank and Evil Masterminds?
- (a)
The Think Tank Lost
- (b)
Evil Masterminds Lost
- (c)
Evil Masterminds Lost
- (d)
Insufficient information provided
Answer: Option B
Text Explanation :
The given table is as follows.
Consider TC’s points breakup. It won against GH and DB. It has two ties. Looking at the points breakups of the Teams in group 2, we can see that only TI and SE could have tied against TC. Thus, TC lost against EM.
Now, since SE has ties against TC and GR and won against TP, it must have lost its remaining matches.
EM won against TP and TC. Thus, it must have lost against GR, SS and TTT.
The table now becomes as given below.
GR must have lost against TI, GH and DB.
TTT could have only tied against GH. Thus, it lost against TI.
TI won against GR and TTT and tied against TC. Thus, it must have lost against TP and SS.
Thus, TP must have tied against GH and DB SS lost against GH and DB.
Thus, the final table looks as given below.
Thus, Evil Masterminds lost against The Think Tank.
Hence, the answer is option B.
Workspace:
Tech Pirates had a tie against which of the following team(s)?
I. Team Intelligence
II. Screaming Eagles
III. Dr Bigbull
IV. Golden Hawks
Choose the correct option?
- (a)
Only I
- (b)
Both II and III
- (c)
Only III
- (d)
Both III and IV
Answer: Option D
Text Explanation :
The given table is as follows.
Consider TC’s points breakup. It won against GH and DB. It has two ties. Looking at the points breakups of the Teams in group 2, we can see that only TI and SE could have tied against TC. Thus, TC lost against EM.
Now, since SE has ties against TC and GR and won against TP, it must have lost its remaining matches.
EM won against TP and TC. Thus, it must have lost against GR, SS and TTT.
The table now becomes as given below.
GR must have lost against TI, GH and DB.
TTT could have only tied against GH. Thus, it lost against TI.
TI won against GR and TTT and tied against TC. Thus, it must have lost against TP and SS.
Thus, TP must have tied against GH and DB SS lost against GH and DB.
Thus, the final table looks as given below.
Thus, TP had a tie against GH and DB.
Hence, the answer is option D.
Workspace:
Following are four statements:
I. Golden Hawks won the presentation round against Super Sellers.
II. Evil Masterminds won the presentation round against Ghost Riders.
III. Screaming Eagles won the presentation round against The Think Tank.
IV. The presentation round between The Capitalist and Team Intelligence resulted in atie.
Choose the correct option:
- (a)
Statement I is true, and Statement II is false.
- (b)
Both statement II and Statement IV are true.
- (c)
Only statement I is true.
- (d)
Only statement III is false.
Answer: Option A
Text Explanation :
The given table is as follows.
Consider TC’s points breakup. It won against GH and DB. It has two ties. Looking at the points breakups of the Teams in group 2, we can see that only TI and SE could have tied against TC. Thus, TC lost against EM.
Now, since SE has ties against TC and GR and won against TP, it must have lost its remaining matches.
EM won against TP and TC. Thus, it must have lost against GR, SS and TTT.
The table now becomes as given below.
GR must have lost against TI, GH and DB.
TTT could have only tied against GH. Thus, it lost against TI.
TI won against GR and TTT and tied against TC. Thus, it must have lost against TP and SS.
Thus, TP must have tied against GH and DB SS lost against GH and DB.
Thus, the final table looks as given below.
Hence, the answer is option A.
Workspace:
Read the following passage:
In 2021, IIFT has announced the “Student of the year” competition which has twosteps: - the preliminary stage and the final stage. The preliminary stage comprised of overall academic excellence in the five trimesters of the coursework. When the results of the preliminary stage were announced, it was found that only five students -Aavanya, Aarav, Saanvi, Vagisha, and Raghav qualified to compete in the final stage of “Student of the year 2021” competition. In the final stage there were five rounds of extra-curricular activities wherein the students could score from 1 to 10 points in each round. These five extra-curricular activity rounds were Debate, Extempore, Business quiz, B-plan competition, and Case Study analysis. The student with maximum points across these five rounds would be considered as winner and would take the prestigious trophy of “Student of the year 2021”.
So at the end of these five rounds of competitions, when the Jury asked for the scorecard to find out the final winner, the scorer informed them that due to some technical glitches several entries have been deleted and jury was presented with following table:
However, the scorer has made the following observations too:
(i) No two students have scored equal points in the same round.
(ii) Vagisha has scored an odd number point in case study analysis round.
(iii) Aarav’s total score point was in the multiple of 8, and it was the least among all.
(iv) There was no tie between any two students in the overall/total points.
(v) Vagisha has scored same points in the following rounds: Debate round, and Extempore round.
(vi) None of the missing scores were less than 4 in any round.
(vii) Aavanya won the competition and won the prestigious trophy of “Student of the year 2021
Choose the correct pair of possibilities:
Possibility I: Raghav scored 8 points in debate round.
Possibility II: Vagisha's score in extempore round is twice of Aarav in the same round.
Possibility III: Vagisha scored 6 points in the debate round.
Possibility IV: Vagisha scores more points than Aavanya in the business quiz round.
- (a)
Possibility I and possibility II are true.
- (b)
Possibility II and possibility III are true.
- (c)
Only Possibility III is true.
- (d)
Possibility I and possibility IV are true.
Answer: Option C
Text Explanation :
no two students have scored equal points in the same round.
Let Vagisha's score in the Debate and Extempore rounds be x. Thus, the table becomes as shown below.
Possibility (I): Raghav scored 8 points in the debate round.
The total value of the blanks will be = 29 − 8 − 3 − 10 = 7. Since each of the blanks has at least 4 points, this case is not possible.
Possibility (II): Vagisha's score in the extempore round is twice of Aarav's in the same round.
Thus, x = 8 or 10
If x = 8, the total of remaining blanks = 33 - 8 - 8 - 8 = 9. The only possible values for the blanks are 4 and 5. Since, Both BP and CP already have 4 points, Vagisha cannot get 4 points. Thus, this case is not possible.
If , the total of remaining blanks = . Thus, this case is also not possible.
Possibility (III): Vagisha scored 6 points in the debate round.
If x = 6, the total of remaining blanks = 33 - 8 - 6 - 6 = 13. In this case, the remaining scores can be 6 and 7, respectively, such that it satisfies the condition in statement 2. Thus, this case is possible.
Possibility (IV): Vagisha scores more points than Aavanya in the business quiz round.
Let Vagisha scores 8 points in BQ and x = 4. Thus, Vagisha's points in the CP round = 33 - 4 - 4 - 8 - 8 = 9. Since Aavanya already scored 9 points in CP, this is not possible.
Let Vagisha scores 8 points in BQ and x = 6. Thus, Vagisha's points in the CP round = 33 - 8 - 6 - 6 - 8 = 5. This looks plausible but in this case, Raghav's possible points do not fit the conditions.
Similarly, for other cases, this possibility is found to be invalid.
Hence, the answer is option C.
Workspace:
If Aavanya scores 5 points in the B-plan competition round, and sum of twoof the three missing values for Raghav is a prime number, then which possibility iscorrect?
Possibility I: Raghav has scored 5 points in Case-study analysis round.
Possibility II: Raghav has scored 5 points in Debate round.
Possibility III: Raghav has scored 4 points in Debate round.
- (a)
Possibility I alone is definitely false.
- (b)
Possibility II alone is definitely true
- (c)
Possibility III alone is definitely true.
- (d)
All possibilities are true.
Answer: Option D
Text Explanation :
1, no two students have scored equal points in the same round.
Let Vagisha's score in the Debate and Extempore rounds be x. Thus, the table becomes as shown below.
Possibility I:
In the previous question, we have seen that Vagisha cannot score 8 in BQ. Thus, the only possibility for her score is as given in the table below.
Thus, the sum of Raghav’s points in the remaining two rounds = 29 - 3 - 10 - 5 = 11 which is a prime number. Hence, statement 1 is a possibility.
Possibility II:
The sum of scores of BP and CP is 11, i.e. a prime number.
Thus, statement 2 is also a valid possibility.
Possibility III:
The sum of scores of BP and Debate is 11, i.e. a prime number.
Thus, statement 3 is also a valid possibility.
Hence, the answer is option D.
Workspace:
Suppose, if Saanvi scores 5 points in Debate round, still wins the "Studentof the Year" trophy by scoring one more point than "Aavanya" in total score; andRaghav has been given opportunity to re-appear for any two rounds, how manycombinations Raghav can choose to win prestigious "Student of the Year" trophy:
- (a)
3
- (b)
4
- (c)
5
- (d)
6
Answer: Option B
Text Explanation :
Workspace:
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