LR - Operator Based Questions - Previous Year CAT/MBA Questions
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Choose 1; if the question can be answered by using one of the statements alone, but cannot be answered using the other statement alone.
Choose 2; if the question can be answered by using either statement alone.
Choose 3; if the question can be answered by using both statements together, but cannot be answered using either statement alone.
Choose 4; if the question cannot be answered even by using both statements together.
For any two real numbers
a ⊕ b = 1 if both a and b are positive or both a and b are negative.
= –1 if one of the two numbers a and b is positive and the other negative.
What is (2 ⊕ 0) ⊕ (–5 ⊕ –6)?
- a ⊕ b is zero if a is zero.
- a ⊕ b = b ⊕ a
- (a)
1
- (b)
2
- (c)
3
- (d)
4
Answer: Option C
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Text Explanation :
(2 ⊕ 0) ⊕ (–5 ⊕ –6)
= (2 ⊕ 0) ⊕ 1
From statement A
(0 ⊕ 2) = 0 but we don’t know the value of (2 ⊕ 0).
∴ Statement A alone is not sufficient to answer the question.
From statement B
(2 ⊕ 0) = (0 ⊕ 2)
∴ Statement B alone is not sufficient to answer the question.
After combining both the statements, we get,
(2 ⊕ 0) = (0 ⊕ 2) = 0
∴ (2 ⊕ 0) ⊕ (–5 ⊕ –6)
= (2 ⊕ 0) ⊕ 1
= 0 ⊕ 1
= 0
∴ Both the statements are required to answer the question.
Hence, option (c).
Workspace:
Direction: Answer the question based on the following information.
The following operations are defined for real numbers.
a # b = a + b, if a and b both are positive else a # b = 1
a ∇ b = (a × b)a + b if a × b is positive else a ∇ b = 1.
- (a)
1/8
- (b)
1
- (c)
3/8
- (d)
3
Answer: Option C
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Text Explanation :
Since both 2 and 1 are positive, (2 # 1) = 2 + 1 = 3.
(1∇2)= (1× 2)1+2 = 23 = 8.
Thus, the given expression is equal to
Workspace:
- (a)
3/8
- (b)
- (c)
- (d)
None of these
Answer: Option A
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Text Explanation :
Let us first simplify the numerator. Since 1 is positive,
(1 # 1) is 1 + 1 = 2 which again is positive. Then
(1 # 1) # 2 = 2 # 2 = 2 + 2 = 4
Now note that log10 0.1
= log10 10–1 = –1
Then 101.3 log10 0.1= 101.3 × (–1) is negative.
So 101.3 ∇ log10 0.1 = 1
Hence, the numerator is equal to 4 –1 = 3
Since 1 × 2 = 2 is positive, (1∇2) = (1× 2)1+2 = 23 = 8.
So the denominator = 8. Hence, the answer is
Workspace:
then which of the following must be true?
- (a)
X = 2, Y = 1
- (b)
X > 0, Y < 0
- (c)
X, Y both positive
- (d)
X, Y both negative
Answer: Option B
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Text Explanation :
The best possible way to solve this is to check each of the given answer choices. In options (a), (c) and (d), either both X and Y are positive or both X and Y are negative.
Since we have (–Y) in the numerator of our expression and (–X) in the denominator, X and Y will never be both positive and neither will XY be positive.
Hence, both the numerator and the denominator of our expression will be 1 and the value will always be 1.
Hence, the only possible answer choice is (b).
Workspace:
If 8 + 12 = 2, 7 + 14 = 3 then 10 + 18 = ?
- (a)
10
- (b)
4
- (c)
6
- (d)
18
Answer: Option A
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Text Explanation :
Here logic is : A + B = (A + B) – 18
Hence, 10 + 18 = {(10 + 18) – 18} = 10.
Hence, option (a).
Workspace:
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