# LR - Directions - Previous Year CAT/MBA Questions

You can practice all previous year CAT questions from the topic LR - Directions. This will help you understand the type of questions asked in CAT. It would be best if you clear your concepts before you practice previous year CAT questions.

**IIFT 2009 LRDI | LR - Directions**

Mr Raghav went in his car to meet his friend John. He Drove 30 kms towards north and then 40 kms towards west. He then turned to south and covered 8 kms. Further he turned to east and moved 26 kms. Finally he turned right and drove 10 kms and then turned left to travel 19 kms. How far and in which direction is he from the starting point?

- A.
East of starting point, 5 kms

- B.
East of starting point, 13 kms

- C.
North East of starting point, 13 kms

- D.
North East of starting point, 5 kms

Answer: Option C

**Explanation** :

From the directions given in the questions following diagram can be drawn:

The distance between the Starting point and the final position of Mr. Raghav can be determined using Pythagoras theorem with the two sides as 12 and 5.

∴ Mr. Raghav is 13 kms to the North east of the starting point.

Hence, option (c).

Workspace:

**Answer the following question based on the information given below.**

In a country, the following signals are applicable:

A man headed towards north and follows the given signals as:

**CAT 2002 LRDI | LR - Directions**

What is the total distance covered by the man till the last signal?

- A.
90 km

- B.
120 km

- C.
110 km

- D.
84 km

Answer: Option A

**Explanation** :

The movement can be tabulated as below:

Distance = $20\times \frac{1}{2}+40\times \frac{1}{4}+40\times \frac{1}{2}+100\times \frac{2}{5}+40\times \frac{1}{4}$

= 10 + 10 + 20 + 40 + 10

= 90 km

Hence, option (a).

Workspace:

**CAT 2002 LRDI | LR - Directions**

What is his net displacement with respect to the starting point?

- A.
40 km towards South West

- B.
50 km towards North East

- C.
40 km towards North East

- D.
60 km towards South West

Answer: Option B

**Explanation** :

The map of his movements is as shown below:

∴ The net displacement with respect to the starting point

$=\sqrt{{40}^{2}+{30}^{2}}$ = 50 km towards North-East

Hence, option (b).

Workspace:

**CAT 2002 LRDI | LR - Directions**

If the first signal after the starting point, is 1 Red and 2 Green lights, then what is the total distance covered by the man till the last signal?

- A.
90 km

- B.
50 km

- C.
40 km

- D.
80 km

Answer: Option A

**Explanation** :

Since only the direction of the man has changed, the total distance covered by him will still remain the same.

∴ Total distance = 90 km

Hence, option (a).

Workspace:

**CAT 2002 LRDI | LR - Directions**

Instead of heading North, if the man was heading South, then by the end of the journey, he was

- A.
50 km towards South, 50 km towards West from his starting point.

- B.
50 km towards North, 50 km towards West from his starting point.

- C.
60 km towards North, 40 km towards West from his starting point.

- D.
40 km towards South, 30 km towards West from his starting point.

Answer: Option D

**Explanation** :

If instead of North, the man headed for South, the map given in the solution of the second question in the set will get inverted and flipped.

∴ He will end up south-west of his starting position, instead of north-east.

∴ He ends up at 30 km West and 40 km South of his starting point.

Hence, option (d).

Workspace:

**CAT 1991 LRDI | LR - Directions**

A man starting at a point walks one km east, then two km north, then one km east, then one km north, then one km east and then one km north to arrive at the destination. What is the shortest distance from the starting point to the destination?

- A.
2√2 km

- B.
7 km

- C.
3√2 km

- D.
5 km

Answer: Option D

**Explanation** :

Following diagram shows the movement of the man.

∴ OQ = $\sqrt{{3}^{2}+{4}^{2}}$ = 5 km.

Hence, option (d).

Workspace:

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