CRE 2 - Using letters of a word | Modern Math - Permutation & Combination
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Answer the next 10 questions based on the information given:
Consider the letters of the word “JOURNEY”. Using the letters of this word,
How many 7 letter words can be formed?
Answer: 5040
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Explanation :
Number of ways of arranging 7 letters = 7! = 5040.
Hence, 5040.
Workspace:
How many 7 letter words starting with O can be formed?
Answer: 720
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Explanation :
If the first position is occupied by O, we have 6 positions left which will be occupied by 6 letters.
∴ Number of words = 6! = 720.
Hence, 720.
Workspace:
How many 7 letter words ending with Y can be formed?
Answer: 720
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Explanation :
If the last position is occupied by Y, we have 6 positions left which will be occupied by 6 letters.
∴ Number of words = 6! = 720.
Hence, 720.
Workspace:
How many 7 letter words starting with O & ending with Y can be formed?
Answer: 120
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Explanation :
If the first position is occupied by O and last by Y, we have 5 positions left which will be occupied by 5 letters.
∴ Number of words = 5! = 120.
Hence, 120.
Workspace:
How many 7 letter words starting with O or ending with Y can be formed?
Answer: 120
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Explanation :
Number of words starting with O or ending with Y = O + Y – O ∩ Y.
O = Number of words starting with O = 720.
Y = Number of words ending with Y = 720.
O ∩ Y = Number of words starting with O & ending with Y = 120.
∴ O + Y – O ∩ Y = 720 + 720 – 120 = 1320.
Hence, 1320.
Workspace:
How many 7 letter words neither starting with O nor ending with Y can be formed?
Answer: 3720
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Explanation :
Total number of words = 7! = 5040. (From 1st question)
Number of words starting with O or ending with Y = 1320 (From previous question)
∴ Number of words neither starting with O or ending with Y = 5040 – 1320 = 3720.
Hence, 3720.
Workspace:
How many 7 letter words can be formed such that all the vowels are together?
Answer: 720
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Explanation :
There are three vowel in JOURNEY i.e., E, O and U.
All three vowels are together. Let’s call the group of vowels as X.
⇒ We have 5 letters i.e., J R N Y X which can be arranged in 5! = 120 ways.
For each of these 120 arrangements, internal arrangement of vowels in X can be done in 3! = 6 ways.
∴ Number of words that can be formed such that all the vowels are together = 120 × 6 = 720 ways.
Hence, 720 ways.
Workspace:
How many 7 letter words can be formed such that no two vowels are together?
Answer: 1440
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Explanation :
Let’s first arrange the remaining letters i.e., J, R, N, and Y
Number of ways of arranging these 4 letters = 4! = 24 ways.
Let’s take one of these arrangements as J R N Y.
Now we have 5 places to arrange the remaining 3 vowels i.e., | J | R | N | Y|.
Hence, 3 vowels can be arranged in 5 places in 5 × 4 × 3 = 60 ways.
∴ Total number of words that can be formed such that no two vowels are together = 24 × 60 = 1440.
Hence, 1440.
Workspace:
How many 7 letter words can be formed such that all the vowels are not together?
Answer: 4320
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Explanation :
Total number of words = 7! = 5040. (From 1st question)
Number of words where all the vowels are together = 720 ways.
∴ Number of words that can be formed such that all the vowels are not together = 5040 – 720 = 4320.
Hence, 4320.
Workspace:
What is the rank of the word “JOURNEY” among all the 7 letter words that can be formed using its letters in dictionary order?
Answer: 1047
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Explanation :
Let’s first arrange all the letters in alphabetical order i.e., E J N O R U Y.
Let the position of letters be: 1 2 3 4 5 6 7
Letter at 1st place:
Number of words starting with E = 6! = 720.
All these words will come before ‘JOURNEY’. From 721st word onwards, first letter will be J.
J 2 3 4 5 6 7
Letter at 2nd place:
Number of words with E at 2nd place = 5! = 120.
Number of words with N at 2nd place = 5! = 120.
Total 720 + 240 = 960 words.
All these words will come before ‘JOURNEY’. From 961st word onwards, 1st letter will be J and 2nd letter will be O.
J O 3 4 5 6 7
Letter at 3rd place:
Number of words with E at 3rd place = 4! = 24.
Number of words with N at 3rd place = 4! = 24.
Number of words with R at 3rd place = 4! = 24.
Total 960 + 24 + 24 + 24 = 1032 words.
All these words will come before ‘JOURNEY’. From 1033rd word onwards, 1st letter will be J, 2nd letter will be O and 3rd letter will be U.
J O U 4 5 6 7
Letter at 4th place:
Number of words with E at 4th place = 3! = 6.
Number of words with N at 4th place = 3! = 6.
Total 1032 + 6 + 6 = 1044 words.
All these words will come before ‘JOURNEY’. From 1045th word onwards, 1st letter will be J, 2nd letter will be O, 3rd letter will be U and 4th letter will be R.
J O U R 5 6 7
Letter at 5th place:
Number of words with E at 5th place = 2! = 2.
Total 1044 + 2 = 1046 words.
All these words will come before ‘JOURNEY’. From 1047th word onwards, 1st letter will be J, 2nd letter will be O, 3rd letter will be U, 4th letter will be R and 5th letter will be N.
J O U R N 6 7
Now, 1047th word will have E at 6th and Y at 7th position which makes the work J O U R N E Y.
∴ JOURNEY is ranked 1047th.
Hence, 1047.
Workspace:
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