# PE 5 - Puzzles | LR - Puzzles

Join our Telegram Channel for CAT/MBA Preparation.

**Answer the next 4 questions based on the information given below.**

The watchmaker created a timepiece with a short and long hand, which differs from traditional watches in that it has eight equal divisions on its face rather than the usual twelve. The long hand requires the same amount of time to travel one division as the short hand does to complete a full rotation. It takes 12 hours for the long hand to make one full rotation. When the time is 12 PM, both hands are directed towards the 8th division. The eight divisions on the watch face are identified with the letters A through H, but they are not arranged in any particular order.

- When the time is 4:30 pm, the short hand points towards C, while the long hand points towards E.
- At 7:30 pm, the long hand points towards F.
- A is equidistant from E and F.
- Labels D and H are opposite to each other.
- Starting anti-clockwise from E, B comes after G.

**PE 5 - Puzzles | LR - Puzzles**

What is the angle between short and long hand at 6 pm?

[Write your answer as nearest integer in degrees.]

Answer: 180

Join our Telegram Channel for CAT/MBA Preparation.

**Explanation** :

Time taken by the long hand to complete one full revolution (8 divisions) is 12 hours.

∴ Time taken by long hand to complete one division = 12/8×60 = 90 minutes.

Hence, it takes 90 minutes for short hand to travel one full round and for long hand to travel one division.

From (1): Till 4:30, (4 × 60 + 30 =) 270 minutes have passed.

⇒ The short hand must have completed (270/90 =) 3 rounds, while

The long hand must have travelled three divisions.

⇒ The short hand is pointing towards division 8 while long hand is pointing towards division 3.

⇒ Division 8 is labelled C, while division 3 is labelled E.

From (2): Till 7:30, (7 × 60 + 30 =) 450 minutes have passed.

⇒ The short hand must have completed (450/90 =) 5 rounds, while

The long hand must have travelled five divisions.

⇒ The short hand is pointing towards division 8 while long hand is pointing towards division 5.

⇒ Division 5 is labelled F.

From (3): A is equidistant from F and E.

⇒ This is possible only when division 4 is labelled A.

From (4): Labels D and H are opposite to each other.

⇒ This is possible when divisions 2 and 6 are labelled D or H in any order.

From (5): Division 1 is labelled G, while division 7 is labelled B.

∴ Till 6 pm, (6 × 60 =) 360 minutes have passed.

⇒ Long hand must have travelled (360/90 =) 4 divisions i.e., pointing at 4^{th} division.

⇒ Short hand must have travelled 4 complete rounds i.e., pointing at 8^{th} division.

∴ The angle between the two hands will be 180 degrees.

Hence, 180.

Workspace:

**PE 5 - Puzzles | LR - Puzzles**

Which division is labelled B?

- (a)
1

- (b)
3

- (c)
5

- (d)
7

Answer: Option D

Join our Telegram Channel for CAT/MBA Preparation.

**Explanation** :

Consider the solution to the first question of this set.

Division 7 is labelled as B.

Hence, option (d).

Workspace:

**PE 5 - Puzzles | LR - Puzzles**

What is the time when long hand points towards D and short hand points towards 8?

- (a)
6 pm

- (b)
3 pm

- (c)
9 pm

- (d)
Cannot be determined

Answer: Option D

Join our Telegram Channel for CAT/MBA Preparation.

**Explanation** :

Consider the solution to the first question of this set.

Since the position of D is not fix, we cannot determine the required time.

Hence, option (d).

Workspace:

**PE 5 - Puzzles | LR - Puzzles**

What is the time when long hand points exactly between A and F?

- (a)
7 pm

- (b)
6:30 pm

- (c)
6:45 pm

- (d)
None of these

Answer: Option C

Join our Telegram Channel for CAT/MBA Preparation.

**Explanation** :

Consider the solution to the first question of this set.

Let us first calculate the time when the long hand points towards A and short hand points towards C.

The long hand has travelled exactly 4 divisions, hence time elapsed = 4 × 90 = 360 minutes = 6 hours.

∴ At 6 pm, the long hand points towards A.

For long hand to point exactly between A and F, another 45 minutes must have passed.

∴ The required time = 6:45 pm.

Hence, option (c).

Workspace:

**Answer the next 5 questions based on the information given below.**

In the game of cricket, the game starts with 2 batsmen at the crease. The goal of these batsmen is to score as many runs as possible. Runs can only be scored by the 2 batsmen at the crease or through extras. Extra runs are added to the team total but they are not attributed to any of the batsmen. Team’s total score is sum of all the runs scored by all the batsmen who have batted till that point plus the extra runs.

In the process of making runs a batsman can get out. If a batsman gets out, he no longer is part of the game and is replaced by another batsman.

The following list gives the number of runs scored by the Indian batsmen in a match. The batsmen are given in the order in which they came to bat.

The values below give the score of the team at which the wickets fell.

1 – 27, 2- 56, 3 – 76, 4 – 108, 5 – 140, 6 – 177, 7 – 204, 8 – 216, 9 – 223 and 10 – 243.

**PE 5 - Puzzles | LR - Puzzles**

What was India’s score when Kohli got out?

Answer: 108

Join our Telegram Channel for CAT/MBA Preparation.

**Explanation** :

The first two batsmen on the crease are Jaiswal and Faff.

1^{st} wicket falls at 27.

Since, Faff has to score 28 runs he cannot get out when team’s score is less than 28.

∴ 1^{st} batsman to get out is Jaiswal.

Jaiswal gets out with a score of 17, hence the remaining (27 – 17 =) 10 runs were total of Faff and extras till that point.

Now, Kohli comes out to bat along with Faff.

2^{nd} wicket falls at 56.

(56 – 27 =) 29 runs have been scored between 1st and 2nd wicket.

Since Kohli has to score 33 runs, he cannot get out as 2nd wicket.

∴ 2^{nd} batsman to get out is Faff.

Faff get out with a score of 28. Total runs made by batsmen who have got out = 17 + 28 = 45.

∴ Remaining (56 – 45 =) 11 runs were total of Kohli and extras till that point.

Now, Samson comes out to bat with Kohli.

Similarly, we can complete the table as shown below.

India’s score when Kohli got out was 108.

Hence, 108.

Workspace:

**PE 5 - Puzzles | LR - Puzzles**

What was India’s score when SKY got out?

Answer: 177

Join our Telegram Channel for CAT/MBA Preparation.

**Explanation** :

Consider the solution to first question of this set.

India's score when SKY got out was 177.

Hence, 177.

Workspace:

**PE 5 - Puzzles | LR - Puzzles**

Who was the other batsman when Miller got out?

- (a)
Cummins

- (b)
Shami

- (c)
Bumrah

- (d)
Shami

Answer: Option C

Join our Telegram Channel for CAT/MBA Preparation.

**Explanation** :

Consider the solution to first question of this set.

Since question mentions that Miller got out, he could get out only as the 10^{th} wicket. The other batsman when Miller gets out would be Bumrah.

Hence, option (c).

Workspace:

**PE 5 - Puzzles | LR - Puzzles**

Which player was out when India’s score was 76?

- (a)
Samson

- (b)
Hardik

- (c)
SKY

- (d)
Cannot be determined

Answer: Option A

Join our Telegram Channel for CAT/MBA Preparation.

**Explanation** :

Consider the solution to first question of this set.

Samson got out when India's score was 76.

Hence, option a).

Workspace:

**PE 5 - Puzzles | LR - Puzzles**

When Hardik got out, how many runs were scored through extras till that point?

- (a)
6

- (b)
7

- (c)
8

- (d)
Cannot be determined

Answer: Option D

Join our Telegram Channel for CAT/MBA Preparation.

**Explanation** :

Consider the solution to first question of this set.

Although we know total extras scored = 243 - (sum of score of all batsmen) = 243 - 235 = 8, but we cannot figure how many extras where scored till Hardik got out.

Hence, option (d).

Workspace:

## Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.