# CRE 2 - Find the day of the week | LR - Calendar

**CRE 2 - Find the day of the week | LR - Calendar**

Which among the following years is a leap year?

- A.
2600

- B.
2700

- C.
2800

- D.
3000

Answer: Option C

**Explanation** :

For a year to be leap year there are 2 conditions

- If it is a non-century year, it should be divisible by 4.

- If it is a century year, it should be divisible by 400.

Here all the given years are century years, and only 2800 is divisible by 400.

Hence, 2800 is a leap year.

Hence, option (c).

Workspace:

**CRE 2 - Find the day of the week | LR - Calendar**

What was the day on 1^{st} Jan 1901?

- A.
Wednesday

- B.
Thursday

- C.
Tuesday

- D.
Saturday

Answer: Option C

**Explanation** :

Here we need to break days till 1^{st} Jan 1901.

**Complete years = 1900**

Odd days in first 1600 years = 0

Odd days in next 300 years = 1

∴ Odd days in complete years = 0 + 1 = 1.

**Incomplete year (1901)**

Just 1 day i.e., 1^{st} of January 1901.

∴ Odd days in incomplete year = 1

∴ Total odd days till 1^{st} Jan 1901 = 1 + 1 = 2.

∴ Day of the week on 1st Jan 1901 will be 2 days after Sunday i.e., Tuesday.

Hence, option (c).

Workspace:

**CRE 2 - Find the day of the week | LR - Calendar**

What was the day of the week on 2^{nd} July 1184?

- A.
Thursday

- B.
Wednesday

- C.
Saturday

- D.
Monday

Answer: Option D

**Explanation** :

Here we need to break days till 2^{nd} July 1184.

**Complete years = 1183**

Odd days in first 800 years = 0

Odd days in next 300 years = 1

Odd days in next 83 years (20 leap and 63 non-leap years) = 20 × 2 + 63 × 1 = 103.

∴ Odd days in complete years = 0 + 1 + 103 = 104 odd days.

∴ Odd days in complete years = Remainder (104 ÷ 7) = 6 odd days.

**Incomplete year (1184, a leap year)**

Jan + Feb + Mar = 0 odd days,

Apr + May + Jun = 0 = odd days,

Jul = 2

∴ Odd days in incomplete year = 0 + 0 + 2 = 2 odd days.

∴ Total odd days till 2^{nd} July 1184 = 6 + 2 = 8 = 1 odd day.

∴ Day of the week on 2^{nd} July 1184 will be 1 day after Sunday i.e., Monday.

Hence, option (d).

Workspace:

**CRE 2 - Find the day of the week | LR - Calendar**

What was the day on 31^{st} Oct 1984?

- A.
Sunday

- B.
Wednesday

- C.
Monday

- D.
Thursday

Answer: Option D

**Explanation** :

Here we need to break days till 31^{st} Oct 1984.

**Complete years = 1983**

Odd days in first 1600 years = 0

Odd days in next 300 years = 1

Odd days in next 83 years (20 leap and 63 non-leap years) = 20 × 2 + 63 × 1 = 103.

∴ Odd days in complete years = 0 + 1 + 103 = 104 odd days.

∴ Odd days in complete years = Remainder (104 ÷ 7) = 6 odd days.

**Incomplete year (1984, a leap year)**

Jan + Feb + Mar = 0 odd days,

Apr + May + Jun = 0 = odd days,

Jul + Aug + Sep = 1 odd day

Oct = 31

∴ Odd days in incomplete year = 0 + 0 + 1 + 31 = 32 odd days = 4 odd days.

∴ Total odd days till 31^{st} Oct 1984 = 6 + 4 = 10 odd days = 3 odd days.

∴ Day of the week on 31^{st} Oct 1984 will be 3 days after Sunday i.e., Wednesday.

Hence, option (d).

Workspace:

**CRE 2 - Find the day of the week | LR - Calendar**

What was the day on 14^{th} Mar 2393?

- A.
Tuesday

- B.
Sunday

- C.
Friday

- D.
Saturday

Answer: Option B

**Explanation** :

Here we need to break days till 14^{th} Mar 2393.

**Complete years = 2392**

Odd days in first 2000 years = 0

Odd days in next 300 years = 1

Odd days in next 92 years (23 leap and 69 non-leap years) = 23 × 2 + 69 × 1 = 115.

∴ Odd days in complete years = 0 + 1 + 115 = 116 odd days.

∴ Odd days in complete years = Remainder (116 ÷ 7) = 4 odd days.

**Incomplete year (2393, a non-leap year)**

Jan = 31,

Feb = 28

Mar = 14

∴ Odd days in incomplete year = 31 + 28 + 14 = 73 odd days = 3 odd days.

∴ Total odd days till 14^{th} Mar 2393 = 3 + 4 = 7 odd days = 0 odd days.

∴ Day of the week on 14^{th} Mar 2393 will be 0 days after Sunday i.e., Sunday.

Hence, option (b).

Workspace:

**CRE 2 - Find the day of the week | LR - Calendar**

On what dates of Aug 1980 did Monday fall?

- A.
4

^{th}, 11^{th}, 18^{th}, and 25^{th} - B.
3

^{rd}, 10^{th}, 17^{th}and 24^{th} - C.
6

^{th}, 13^{th}, 20^{th}and 27^{th} - D.
9

^{th}, 16^{th}, 23^{rd}and 30^{th}

Answer: Option A

**Explanation** :

Let us first calculate the day of the week on 1^{st} August 1980.

Here we need to break days till 1^{st} August 1980.

**Complete years = 1979**

Odd days in first 1600 years = 0

Odd days in next 300 years = 1

Odd days in next 79 years (19 leap and 60 non-leap years) = 19 × 2 + 60 × 1 = 98.

∴ Odd days in complete years = 0 + 1 + 98 = 99 odd days.

∴ Odd days in complete years = Remainder (99 ÷ 7) = 1 odd days.

**Incomplete year (1980, a leap year)**

Jan + Feb + Mar = 0 odd days,

Apr + May + Jun = 0 odd days,

Jul = 31

Aug = 1

∴ Odd days in incomplete year = 0 + 0 + 31 + 1 = 32 odd days = 4 odd days.

∴ Total odd days till 1^{st} August 1980 = 1 + 4 = 5 odd days.

∴ Day of the week on 1^{st} August 1980 will be 5 days after Sunday i.e., Friday.

Since 1^{st} August 1980 is Friday, next Monday will be on 4^{th} August.

Hence Mondays in August 1980 will be on 4^{th}, 11^{th}, 18^{th} and 25^{th}.

Hence, option (a).

Workspace:

**CRE 2 - Find the day of the week | LR - Calendar**

The calendar for year 2007 is same as calendar of which of these years?

- A.
2011

- B.
2013

- C.
2018

- D.
2020

Answer: Option D

**Explanation** :

For the calendar to be same the year should be a non-leap year and the number of odd days should be 0.

Here, we will calculate the total odd days from 1st Jan of 2007 till 1^{st} Jan of the year.

2007 – 2008 = 1 odd day

2008 – 2009 = 2 odd days (Total 3 odd days)

2009 – 2010 = 1 odd day (Total 4 odd days)

2010 – 2011 = 1 odd day (Total 5 odd days)

2011 – 2012 = 1 odd day (Total 6 odd days)

2012 – 2013 = 2 odd day (Total 8 odd days)

2013 – 2014 = 1 odd day (Total 9 odd days)

2014 – 2015 = 1 odd day (Total 10 odd days)

2015 – 2016 = 1 odd day (Total 11 odd days)

2016 – 2017 = 2 odd day (Total 13 odd days)

2017 – 2018 = 1 odd day (Total 14 odd days = 0 odd days)

Now, 2018 is also a non-leap year like 2007 and odd days from 2007 till 2018 are 0.

∴ Calendar of 2018 will be same as calendar of 2007.

Hence, option (d).

Workspace:

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