PE 3 - Arrangements | LR - Arrangements

Answer: Option C

Explanation :

Let us arrange all patients in increasing order of time spent at the clinic

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Checking for 1^st patient of the three doctors:

Paras: The first patient for Paras must have been in the clinic for 6-10 minutes. This is only possible when Dheeraj was his first patient.

Rohit: The first patient for Rohit must have been in the clinic for 11-15 minutes. Therefore Karan or Lokesh could be his first patient.

Shushant: The first patient for Shushant must have been in the clinic for 16-20 minutes. This is only possible when Charu was his first patient.

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Checking for 2^nd patient of the three doctors:

Paras: Since Dheeraj spent 8 minutes in the clinic, the second patient for Paras must have spent at least (8 + 6 =) 14 minutes and at most (8 + 10 =) 18 minutes. This is only possible when Lokesh was his second patient.

⇒ Karan is the first patient for Rohit

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Rohit: Since Karan spent 12 minutes in the clinic, the second patient for Rohit must have spent at least (12 + 11 =) 23 minutes and at most (12 + 15 =) 27 minutes. This is only possible when Ishan was his second patient.

Shushant: Since Charu spent 17 minutes in the clinic, the second patient for Shushant must have spent at least (17 + 16 =) 33 minutes and at most (17 + 20 =) 37 minutes. This is possible when one of Bhanu or Gautam was his second patient.

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Checking for 3^rd patient of the three doctors:

Paras: Since Lokesh spent 14 minutes in the clinic, the third patient for Paras must have spent at least (14 + 6 =) 20 minutes and at most (14 + 10 =) 24 minutes. This is only possible when Hardik was his third patient.

Rohit: Since Ishan spent 23 minutes in the clinic, the third patient for Rohit must have spent at least (23 + 11 =) 34 minutes and at most (23 + 15 =) 38 minutes. This is only possible when Bhanu was his third patient.

⇒ Shushant’s second patient is Gautam

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Shushant:Since Gautam spent 33 minutes in the clinic, the third patient for Shushant must have spent at least (33 + 16 =) 49 minutes and at most (33 + 20 =) 53 minutes. This is possible when Jitesh or Aman was his third patient.

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Checking for 4^th patient of the three doctors:

Paras: Since Hardik spent 21 minutes in the clinic, the fourth patient for Paras must have spent at least (21 + 6 =) 27 minutes and at most (21 + 10 =) 31 minutes. This is only possible when Ekta was his fourth patient.

Rohit: Since Bhanu spent 37 minutes in the clinic, the fourth patient for Rohit must have spent at least (37 + 11 =) 48 minutes and at most (37 + 15 =) 52 minutes. This is possible when Jitesh or Aman was his fourth patient.

Shushant: This leaves us with Faiz who will be the fourth patient for Shushant.

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Since Faize is the fourth patient for Shushant, the third patient must have spent at least (70 – 20 =) 50 minutes and at most (70 – 16 =) 54 minutes in the clinic. 

⇒ Third patient for Shushant can only be Aman while Jitesh is fourth patient for Rohit.

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Paras consulted Ekta.

Hence, option (c).

Answer: 14

Explanation :

Consider the solution to first question of this set.

Maximum time that Rohit took to consult any patient is 14 minutes for Bhanu.

Hence, 14.

Answer: Option B

Explanation :

Consider the solution to first question of this set.

Jitesh was not consulted by Shushant.

Hence, option (b).

Answer: Option B

Explanation :

Consider the solution to first question of this set.

Aman took the maximum time (19 minutes) for consultation.

Hence, option (b).

Answer: 49

Explanation :

Consider the solution to first question of this set.

Rohit spent a total of (12 + 11 + 14 + 12 =) 49 minutes with his patients.

Hence, 49.

Answer: Option B

Explanation :

From (1) and (4) we can say than Vikas must be 3rd, 4th or 5th person to visit the café.

Case 1: If Vikas is 3rd to visit the café, then Inder and Prakash must be 1st and 2nd respectively to visit the café.
From (5): Achal and Harshit must be 5th and 6th to visit the café.

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From (2): Inder must have had Momos while Prakash must have had Cheese Balls, but this violates condition (1) and (4). Hence this case is rejected.

Case 2: If Vikas is 4th to visit the café, the one who had sandwich would be 5th to visit the case.
Inder and Prakash must have visited before Vikas.So now, it would not be possible to arrange Achal and Harshit since Achal does not order sandwich.m
Hence, this case is also rejected.

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Case 3: If Vikas is 5th to visit the café, the one who had sandwich would be 6th to visit the case.

Inder and Prakash should be one after other while Achal and Harshit must be one after the other. 

We have two cases for this.

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Case 3 (a): Since momos is had just before cheese balls, this is only possible when Prakash ordered moms and Achal orders cheese balls. [Momos cannot be had by the 1st visitor.]. Also this leaves Kunal who ordered Sandwich.

Case 3 (b): Since momos is had just before cheese balls, this is only possible when Inder ordered moms and Prakash orders cheese balls. But this violates condition (4).

∴ Only Case 3 (a) is possible.

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Hence, option (b).

Answer: Option D

Explanation :

Consider the solution for the first question of this set.

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3 people i.e., Inder, Prakash and Achal visited before Harshit.

Hence, option (d).

Answer: Option C

Explanation :

Consider the solution for the first question of this set.

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Harshit visited before the person who had falafel and he ordered a brownie.

Hence, option (c).

Answer: Option B

Explanation :

Consider the solution for the first question of this set.

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Cheese Balls and Brownie were had consecutively.

Hence, option (b).

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