On a square table having 4 chairs on each side?
Explanation:
Here, initially seats 1, 5, 9 and 13 are similar.
Similarly, from the figure, there are 4 different pair of seats i.e., (1, 5, 9, 13), (2, 6, 10, 14), (3, 7, 11, 15) and (4, 8, 12, 16).
Hence, the first person can be seated in 4 different ways on one seat out of the 4 different pairs of seats.
Once the first person is seated, the remaining 15 seats become different from each other.
∴ 15 people can be seated on these 15 different chairs in 15!
⇒ Total number of ways = 4 × 15!
Hence option (d).
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