Discussion

Question:

The value of $[3 \log (\frac{81}{80}) + 5 \log (\frac{25}{24}) + 7 \log (\frac{16}{15})]$ is

Explanation:

Given,

$3 \log \frac{81}{80} + 5 \log \frac{25}{24} + 7 \log \frac{16}{15} = \log [{(\frac{81}{80})}^{3} \times {(\frac{25}{24})}^{5} \times {(\frac{16}{15})}^{7}] = \log (\frac{3^{12} \times 5^{10} \times 2^{28}}{2^{12} \times 5^{3} \times 2^{15} \times 3^{5} \times 3^{7} \times 5^{7}})$

= log⁡2

Hence, option (d).

» Your doubt will be displayed only after approval.

Doubts

Feedback