In ∆ABC, the medians AD and BE meet at G. The ratio of the areas of ∆BDG and the quadrilateral GDCE is?
Explanation:
We also that centroid divides the triangle in 6 smaller triangles of equal areas.
∴ Area(∆BDG) = Area(∆DGC) = Area(∆CGE) = a
⇒ Area(∆BDG) : Area(∆GDCE) = a : 2a = 1 : 2
Hence, option (d).
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