Discussion

Question:

A merchant has 16 kg of sugar, part of which he sells at 10% profit and the rest at 6% profit. He gains 7% on the whole. How much is sold at 6%?

Explanation:

Let the quantity sold at 6% is x kgs and at 10% profit is (16 - x) kgs.

⇒ Overall profit = 7% = $\frac{6 x + 10 (16 - x)}{16}$

⇒ 112 = 6x + 160 – 10x

⇒ x = 12 kgs.

Alternately,

$\frac{Quantity sold at 6 %}{Quantity sold at 10 %}$ = $\frac{3}{1}$

Quantity sold at 6% = $\frac{3}{4}$ × 16 = 12 kgs

Hence, option (c).

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