Discussion

Explanation:

Let Suresh, Harish and Jayant have s, h and j number of candies with them respectively.

If Suresh gives six candies to Jayant, then he is left with s − 6 candies and Jayant now has j + 6 candies.

∴ s - 6 = j + 6 + 4

⇒ s = j + 16   …(1)

If Harish gives four candies to Jayant, he is now left with h − 4 candies whereas Jayant has j + 6 + 4 = j + 10 candies.

∴ h – 4 = j + 10 + 4

⇒ h = j + 18   …(2)

Adding (1) and (2), 

s + h = 2j + 34

∴ 38 = 2j + 34

∴ j = 2

⇒ Jayant has now j + 10 = 12 candies

Hence, option (d).

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