Suresh, Harish and Jayant had some candies each. Together Suresh and Harish had 38 candies. Even after giving six candies to Jayant, Suresh had four more candies than him. Then Harish gave four of his candies to Jayant and was also left with four more candies than him. How many candies does Jayant have now?
Explanation:
Let Suresh, Harish and Jayant have s, h and j number of candies with them respectively.
If Suresh gives six candies to Jayant, then he is left with s − 6 candies and Jayant now has j + 6 candies.
∴ s - 6 = j + 6 + 4
⇒ s = j + 16 …(1)
If Harish gives four candies to Jayant, he is now left with h − 4 candies whereas Jayant has j + 6 + 4 = j + 10 candies.
∴ h – 4 = j + 10 + 4
⇒ h = j + 18 …(2)
Adding (1) and (2),
s + h = 2j + 34
∴ 38 = 2j + 34
∴ j = 2
⇒ Jayant has now j + 10 = 12 candies
Hence, option (d).
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