Find the value of p if the equations 5x + py = 1 and px + 5y = 4 have unique solution.
Explanation:
Two linear equations:
a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0
have unique solution when a1a2≠b1b2
∴ For the given system of equations,
5p≠p5
⇒ p2 ≠ 25
⇒ p ≠ ±5
Hence, option (c).
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