Ashutosh goes to buy two mobiles, five binoculars and three PCs and realizes he has Rs. 14 less than what is required. He then removes three binoculars from his basket and can buy the remaining items with Rs. 4 left over. If he had tried buying a mobile and three PCs he would have Rs. 34 remaining, then what is the maximum number of PCs that could have been bought by Ashutosh?
Explanation:
Let m, b and p be the cost of mobile, binocular and PC.
Let a be the amount with Ashutosh.
Hence,
2m + 5b + 3p = a + 14 …(1)
2m + 2b + 3p = a – 4 …(2)
(1) – (2)
⇒ b = 6.
Now, 2m + 3p = a – 16 (From (1) ∵ b = 6) …(3)
Also given, m + 3p = a – 34 …(4)
Solving (3) and (4) we get,
⇒ m = 18.
Hence, 3p = a - 52.
As there is no other equation given, the answer cannot be determined
Hence, option (d).
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