Discussion

Explanation:

Let n, l and e be the cost of notebook, pencil and eraser.

Hence, 10n + 5l + 3e = 430    …(1)

and 2n + l = 74

⇒ 10n + 5l = 74 × 5 = 370    …(2)

Solving (1) and (2)

⇒ 3e = 60 ⇒ e = 20. 

We want the value of 6n + 3l + 5e = 3 × (2n + l) + 100 = 3 × 74 + 100 = 322

Hence, 400 – 322 = Rs. 78 would be left.

Hence, option (b).

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