Discussion

Explanation:

Given: 

x - 2y + 3z = 9    …(1)
4x + y - 5z = -6    …(2)
x + 2y + 6z = 22    …(3)

Now, eliminating variable x.

(3) – (1)
⇒ 4y + 3z = 13    …(4)

(3) × 4 – (2)
⇒ 7y + 29z = 94    …(5)

Solving (4) and (5), we get y = 1, z = 3 and x = 2.

Hence, x + y + z = 2 + 1 + 3 = 6.

Hence, option (c).

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