Find the last digit of the following expression.
(75)424 + (39)98 + (72)121
Explanation:
Unit digit of (75)242 = 5.
Power of any number with 5 at the unit’s place will always have a 5 at its units place, irrespective of the positive natural number power.
Also, last digit of 3998 = last digit of 998 = last digit of 92 = 1.
Now, last digit of 72121 = last digit of 2121 = last digit of 21 = 2.
So, basically after every 4th power, the units digit repeats itself.
Thus, the digit at the unit’s place is 5 + 1 + 2 = 8.
Hence, option (a).
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