A thief steals a car at 2:30 p.m. and drives it at 30 km/h. The theft is discovered at 3 p.m. and the owner sets off in another car at 50 km/h. when will he overtake the thief
Explanation:
Here, distance to be covered by the thief and by the owner is same.
Let after 2:30 p.m., owner catches the thief in t hrs.
Then, 30×t=50t-12
⇒t =54hrs
So, the thief is overtaken at 3:45 p.m.
Hence, option (b).
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