Discussion

Question:

Quantity A varies inversely with product of B and C. When B = 3 and C = 24, A = 150. Find A when B = 10 and C = 5.

Explanation:

A ∝ 1/BC

$\frac{A_{1}}{A_{2}} = \frac{B_{2} C_{2}}{B_{1} C_{1}}$

If A₁ = 150, B₁ = 3, C₁ = 24, B₂ = 10 and C₂ = 5,

A₂ = $\frac{A_{1} B_{1} C_{1}}{B_{2} C_{2}}$ = $\frac{150 \times 3 \times 24}{10 \times 5}$ = 216.

Hence, 216.

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