If x754 is divisible by 11 and y246 is divisible by 9, the value of xy could be?
Explanation:
In order for x754 to be divisible by 11,
Sum of digits at odd places (o) = 7 + 4
Sum of digits at even places (e) = x + 5
For this number to be divisible by 11, difference of ‘o’ and ‘e’ should be divisible by 11.
∴ o – e = (7 + 4) – (x + 5) = (6 – x) should be divisible by 11.
⇒ x = 6
In order y246 to be divisible by 9, sum of its digits should be divisible by 9.
∴ y + 2 + 4 + 6 = y + 12 should be divisible by 9.
The only number which satisfies this condition is 6.
Hence y = 6
∴ xy = 66
Hence, option (b).
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