Discussion

Explanation:

The sum of interior angles of a pentagon = 540°

Let the angles of the pentagon be a – 2d, a – d, a, a + d, a + 2d

∴ a – 2d + a – d + a + a + d + a + 2d = 540

∴ 5a = 540

∴ a = 108°

∴ One of the angles must be 108°.

Hence, option (a).

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