Discussion

Explanation:

Let the price of the cheapest magazine i.e. the one at the extreme left be x.

Difference, between the prices of two adjacent magazines is Rs. 2

∴ Price of extreme right or the costliest magazine will be x + 30 × 2 = x + 60
Now, the price of the magazine in middle (the 16th position) = x + 15 × 2 = x + 30

The price of the magazines, adjacent to the one in the middle is x + 28 or x + 32 depending on whether it is on the left or right of the middle magazine respectively.

Suppose, x + 60 = x + 28 + x + 30
∴ x + 60 = 2x + 58
∴ x = 2

And if x + 60 = x + 30 + x + 32
∴ 60 = x + 62
∴ x = −2  (which is not possible)

∴ The adjacent magazine is the one whose price is x + 28 i.e. one to the left of the middle magazine.

Hence, option (a).

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