Thirty-one magazines are arranged from left to right in order of increasing prices. The price of each magazine differs by Rs. 2 from that of each adjacent magazine. For the price of the magazine at the extreme right a customer can buy the middle magazine and an adjacent one. Then:
Explanation:
Let the price of the cheapest magazine i.e. the one at the extreme left be x.
Difference, between the prices of two adjacent magazines is Rs. 2
∴ Price of extreme right or the costliest magazine will be x + 30 × 2 = x + 60 Now, the price of the magazine in middle (the 16th position) = x + 15 × 2 = x + 30
The price of the magazines, adjacent to the one in the middle is x + 28 or x + 32 depending on whether it is on the left or right of the middle magazine respectively.
Suppose, x + 60 = x + 28 + x + 30 ∴ x + 60 = 2x + 58 ∴ x = 2
And if x + 60 = x + 30 + x + 32 ∴ 60 = x + 62 ∴ x = −2 (which is not possible)
∴ The adjacent magazine is the one whose price is x + 28 i.e. one to the left of the middle magazine.
Hence, option (a).
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