Discussion

Explanation:

Water carried by pipe ∝ cross sectional area.

∴ Water carried by pipe with 6 inches = k${\left(\frac{6}{2}\right)}^2$ = 9k and water carried by pipe with 1 inch diameter = k${\left(\frac{1}{2}\right)}^2$ = $\frac{\mathrm{k}}{4}$

∴Number of 1 inch pipes = $\frac{9\mathrm{k}}{\mathrm{k}/4}$ = 36 

Hence, option (c).

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