Discussion

Explanation:

Let us draw DG || AF as shown in the figure.

Since D is the mid-point of AB, AD = DB
Also, since E is the mid-point of CD, CE = ED

​​​​​​​

In ∆CDG, since DG || EF, hence
CF : FG = CE : ED = 1 : 1
⇒ CF = FG   ...(1)

In ∆BAF, since DG || AF, hence
BG : GF = BD : DA = 1 : 1
⇒ BG = GF   ...(2)

From (1) and (2), we get
​​​​​​​BG = GF = FC

∴ BG = GF = FC = ⅓ BC = 2 cm.

Hence, option (c).

» Your doubt will be displayed only after approval.


Doubts


Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.


© 2024 | All Rights Reserved | Apti4All