The number of real values of x satisfying the equation 22x2-7x+5 = 1 is:
Explanation:
Given, 22x2-7x+5 = 1 = 20
⇒ 2x2 - 7x + 5 = 0
⇒ 2x2 - 2x - 5x + 5 = 0
⇒ (2x - 5)(x - 1) = 0
⇒ x = 5/2 or 1
Hence, option (b).
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