Discussion

Explanation:

Given xc2ab×xa2bc×xb2ca

xc2ab×xa2bc×xb2ca

xc3abc×xa3abc×xb3abc

xa3+b3+c3abc

Since, a + b + c = 0, it means a3 + b3 + c3 = 3abc

xcab×xabc×xbca = x3abcabc = x3

Hence, option (a).

» Your doubt will be displayed only after approval.


Doubts


Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.


© 2024 | All Rights Reserved | Apti4All