Find the value of xc2ab×xa2bc×xb2ca& if a + b + c = 0.
Explanation:
Given xc2ab×xa2bc×xb2ca&
= xc2ab×xa2bc×xb2ca
= xc3abc×xa3abc×xb3abc
= xa3+b3+c3abc
Since, a + b + c = 0, it means a3 + b3 + c3 = 3abc
∴ xcab×xabc×xbca = x3abcabc = x3
Hence, option (a).
» Your doubt will be displayed only after approval.
Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.