Find the value of x such that 1225x24 is divisible by both 3 and 8.
Explanation:
For a number to be divisible by 3, the sum of the digits should be divisible by 3.
Here sum of the digits = 1 + 2 + 2 + 5 + x + 2 + 4 = 16 + x. 16 + x is divisible by 3 when x = 2 or 5 or 8.
The number can be 1225224 or 1225524 or 1225824
For a number to be divisible by 8, last 3 digits should be divisible by 8. Both 224 and 824 are divisible by 8, hence 1225224 and 1225824 are also divisible by 8.
∴ 1225224 and 1225824 are divisible by both 2 and 8.
Hence, option (d).
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