In the figure, DE and AE bisect ∠ADC and ∠DAB respectively. AB is parallel to CD. Find m ∠AED.
Explanation:
Let m ∠DAB = 2x and m ∠ADC = 2y
∴ m ∠EAB = m ∠EAD = x and m ∠ADE = m ∠EDC = y
∵ AB and CD are parallel, ∠DAB and ∠ADC are interior angles whose sum is 180°.
∴ 2x + 2y = 180°
∴ x + y = 90°
∴ m ∠AED = 180° − (m ∠EAD + m ∠ADE) = 180° − (x + y) = 180° − 90° = 90°
Hence, option (d).
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