∆ABC circumscribes a circle of radius 4 cm. If the sides of ∆ABC are 13, 14 and 15 respectively, find the area of ∆ABC.
Explanation:
Since ∆ABC circumscribes the circle, it means the circle is the incircle of ∆ABC.
We know that area of a triangle = r × s
where, r is the inradius and s is the semiperimeter of the triangle.
s = (13 + 14 + 15)/2 = 21
⇒ Area = 4 × 21 = 84
Hence, option (a).
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