Discussion

Explanation:

Let us join BC.

​​​​​​​

Now, ∠ABC = ½∠AOC = 25° (angle subtended by chord AC on circle is half of the angle it subtends at the center)

similalry, ∠DCB = ½∠DOB = 20° (angle subtended by chord AC on circle is half of the angle it subtends at the center)

In triangle, BPC, ∠BPD = ∠PCB + ∠PBC (exterior angle is sum of two opposite interior angles)

⇒ ∠BPD = 25° + 20° = 45°

Hence, option (c).

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