Discussion

Explanation:

Consider the solution to first 2 questions of this set.

The slower clock will show correct time every 10 days, while the faster clock will show correct time every 15 days.

Hence, both of them will show correct time every LCM(10, 15) = 30 days.

∴ Both of them will show correct time at 6 a.m. on 31st January.

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