Discussion

Explanation:

∆BDE and ∆CDE lie between same 2 parallel lines, hence the ratio of their areas is same as the ratio of their bases.

⇒ $\frac{\mathrm{area}(∆\mathrm{BDE})}{\mathrm{area}(∆\mathrm{CDE})}$ = $\frac{3}{4}$   ...(1)

Similarly, $\frac{\mathrm{area}(∆\mathrm{ADB})}{\mathrm{area}(∆\mathrm{BDE})}$ = $\frac{3}{2}$   ...(2)

(1) × (2)

⇒ $\frac{\mathrm{area}(∆\mathrm{ADB})}{\mathrm{area}(∆\mathrm{CDE})}$ = $\frac{9}{8}$

Hence, option (b).

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