In the figure given below, ∠ABC = 30°, ∠ADC = 10° and ∠BCD = 20°. Find external ∠BAD.
Explanation:
Let us draw a line joining points C and A and extend it till E.
In ∆ABC, ∠EAB is the exterior angle, hence ∠EAB = ∠ABC + ∠BCA ...(1)
In ∆ADC, ∠EAD is the exterior angle, hence ∠EAD = ∠ADC + ∠DCA ...(2)
(1) + (2)
∠EAB + ∠EAD = ∠ABC + ∠BCA + ∠ADC + ∠DCA ⇒ ∠BAD = ∠ABC + ∠ADC + ∠BCD ⇒ ∠BAD = 30° + 10° + 20° = 60°
Hence, option (d).
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