Discussion

Explanation:

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Step 1: 10 litres is transferred from A to B.
Since A contains only milk initially, 10 litres of milk will be transferred from A to B.
Hence, quantity of milk and water in A and B will be 

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Step 2: 10 litres is transferred from B to A.

Now 10 litres out of 60 litres is transferred from B to A.
⇒ Fraction of solution being transferred = 10/60 = 1/6th 

B has 10 litres of milk.
∴ Quantity of milk transferred from B to A = 10 × 1/6 = 5/3 litres

B has 50 litres of water.
∴ Quantity of water transferred from B to A = 50 × 1/6 = 25/3 litres

Hence, quantity of milk and water in A and B will be 3

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∴ Final quantity of water in jug B (vb) = 125/3 litres
and, final quantity of milk in jug A (va) = 125/3 litres

va = vb

Note: If this entire process is repeated again, still the quantity of water in jug B will be same as quantity of milk in jug A, while quantity of milk in jug B will be same as quantity of water in jug A.

Hence, option (a).

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